comparing two table structure

  • Is there a script which will compare the structure of two tables. one table resides in sql 2005 and the other table resides on 2000 sql server.

    Thanks

  • Many ways to do this. Here is a simple one to get started

    select *

    into #a

    from information_schema.columns a

    where table_name = 'aaa'

    select *

    into #b

    from information_schema.columns b -- add linked server name and db as needed

    where table_name = 'bbb'

    select

    from #a a

    left join #b b -- left/right/full outer as desired

    on a.column_name = b.column_name

    where a.data_type <> b.data_type -- or any of the other fields

  • [font="Verdana"]

    also refer below URL

    http://www.sqlservercentral.com/scripts/Administration/62276/

    Thanks,

    Mahesh

    [/font]

    MH-09-AM-8694

  • Take a peek at this:

    http://www.sqlservercentral.com/scripts/Administration/61813/

    Of course the main sproc that you are looking for in the article is

    sp_table_validation

    It will tell you if they are different but not what the particular schematic differences are.

  • ksullivan (4/4/2008)


    Many ways to do this. Here is a simple one to get started

    select *

    into #a

    from information_schema.columns a

    where table_name = 'aaa'

    select *

    into #b

    from information_schema.columns b -- add linked server name and db as needed

    where table_name = 'bbb'

    select

    from #a a

    left join #b b -- left/right/full outer as desired

    on a.column_name = b.column_name

    where a.data_type <> b.data_type -- or any of the other fields

    Hey, i tried and got this error

    Msg 156, Level 15, State 1, Line 12

    Incorrect syntax near the keyword 'from'.

  • Put a * or name some columns after the last select.

    For example,

    select * -- a.column_name or a.is_nullable etc

    from #a a

    left join #b b -- left/right/full outer as desired

    on a.column_name = b.column_name

    where a.data_type <> b.data_type -- or any of the other fields

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