can any one tell me how to split the given @parameter data into three column of table?

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can any one tell me how to split the given @parameter data into three column of table?

Sivaganesh Tamilvendhan

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Points: 3498
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August 26, 2012 at 11:45 pm

#280161

this is way i tried to split data in parameter
declare @parameter varchar (200)
set @parameter ='1_2_3|4_5_6'
;WITH CTE1 AS(
SELECT LEFT(items, CHARINDEX('_', items)-1) AS ss, SUBSTRING(items, CHARINDEX('_', items)+1 ,100) as col,SUBSTRING(items, CHARINDEX('_', items)+1 ,100) as col1
FROM dbo.characterSplit(@parameter,'|')
)
--INSERT INTO tblAdBlock(AdSpaceId ,Row ,[Column])
SELECT *
FROM CTE1 ;
this is function which i used to split the '|'
ALTER FUNCTION [dbo].[characterSplit](@String varchar(8000), @Delimiter char(1))
returns @temptable TABLE (items varchar(8000))
as
begin
declare @idx int
declare @slice varchar(8000)
select @idx = 1
if len(@String)<1 or @String is null return
while @idx!= 0
begin
set @idx = charindex(@Delimiter,@String)
if @idx!=0
set @slice = left(@String,@idx - 1)
else
set @slice = @String
if(len(@slice)>0)
insert into @temptable(Items) values(@slice)
set @String = right(@String,len(@String) - @idx)
if len(@String) = 0 break
end
iam getting output like this
sscolcol1
12_32_3
45_65_6
plz tell me how to get output like this
sscolcol1
123
456

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Dwain Camps SSC Guru Points: 86978 More actions · Answer 1

First, start with a better string splitter, like the one from Jeff Moden:

http://www.sqlservercentral.com/articles/Tally+Table/72993/

Then use cascading CROSS APPLYs, thusly:

declare @parameter varchar (200)

set @parameter ='1_2_3|4_5_6'

SELECT ss=MAX(CASE c.itemnumber WHEN 1 THEN c.item END)

,col=MAX(CASE c.itemnumber WHEN 2 THEN c.item END)

,col1=MAX(CASE c.itemnumber WHEN 3 THEN c.item END)

FROM (SELECT @parameter) a(parameter)

CROSS APPLY dbo.DelimitedSplit8k(parameter, '|') b

CROSS APPLY dbo.DelimitedSplit8k(item, '_') c

GROUP BY b.ItemNumber

My mantra: No loops! No CURSORs! No RBAR! Hoo-uh![/I]
My thought question: Have you ever been told that your query runs too fast?

My advice:
INDEXing a poor-performing query is like putting sugar on cat food. Yeah, it probably tastes better but are you sure you want to eat it?
The path of least resistance can be a slippery slope. Take care that fixing your fixes of fixes doesn't snowball and end up costing you more than fixing the root cause would have in the first place.

Need to UNPIVOT? Why not CROSS APPLY VALUES instead?[/url]
Since random numbers are too important to be left to chance, let's generate some![/url]
Learn to understand recursive CTEs by example.[/url]
[url url=http://www.sqlservercentral.com/articles/St

Sivaganesh Tamilvendhan Hall of Fame Points: 3498 More actions · Answer 2

thanks

dwain.c

it was working fine

can u plz give one idea is there any chance to avoid null value instead of that replace 0 there in column in this proc itself

declare @parameter varchar (200)

set @parameter ='1_2_3|4_5'

SELECT ss=MAX(CASE c.itemnumber WHEN 1 THEN c.item END)

,col=MAX(CASE c.itemnumber WHEN 2 THEN c.item END)

,col1=MAX(CASE c.itemnumber WHEN 3 THEN c.item END)

FROM (SELECT @parameter) a(parameter)

CROSS APPLY dbo.DelimitedSplit8k(parameter, '|') b

CROSS APPLY dbo.DelimitedSplit8k(item, '_') c

GROUP BY b.ItemNumber

i am getting output like this

sscolcol1

123

45NULL

and trying output like this

sscolcol1

123

450

i tried like this

declare @parameter varchar (200)

set @parameter ='1_2_3|4_5'

SELECT ss=MAX(CASE c.itemnumber WHEN 1 THEN c.item END)

,col=MAX(CASE c.itemnumber WHEN 2 THEN c.item END)

,col1=MAX(CASE c.itemnumber WHEN 3 THEN ISNULL(c.item,0) END)

FROM (SELECT @parameter) a(parameter)

CROSS APPLY dbo.DelimitedSplit8k(parameter, '|') b

CROSS APPLY dbo.DelimitedSplit8k(item, '_') c

GROUP BY b.ItemNumber

Sean Lange SSC Guru Points: 286590 More actions · Answer 3

sivajii (8/27/2012)
thanks
dwain.c
it was working fine
can u plz give one idea is there any chance to avoid null value instead of that replace 0 there in column in this proc itself
declare @parameter varchar (200)
set @parameter ='1_2_3|4_5'
SELECT ss=MAX(CASE c.itemnumber WHEN 1 THEN c.item END)
,col=MAX(CASE c.itemnumber WHEN 2 THEN c.item END)
,col1=MAX(CASE c.itemnumber WHEN 3 THEN c.item END)
FROM (SELECT @parameter) a(parameter)
CROSS APPLY dbo.DelimitedSplit8k(parameter, '|') b
CROSS APPLY dbo.DelimitedSplit8k(item, '_') c
GROUP BY b.ItemNumber
i am getting output like this
sscolcol1
123
45NULL
and trying output like this
sscolcol1
123
450
i tried like this
declare @parameter varchar (200)
set @parameter ='1_2_3|4_5'
SELECT ss=MAX(CASE c.itemnumber WHEN 1 THEN c.item END)
,col=MAX(CASE c.itemnumber WHEN 2 THEN c.item END)
,col1=MAX(CASE c.itemnumber WHEN 3 THEN ISNULL(c.item,0) END)
FROM (SELECT @parameter) a(parameter)
CROSS APPLY dbo.DelimitedSplit8k(parameter, '|') b
CROSS APPLY dbo.DelimitedSplit8k(item, '_') c
GROUP BY b.ItemNumber

You have your isnull check in the wrong spot. You have it inside your case which doesn't do what you want because there is no value in the second row where ItemNumber = 3.

declare @parameter varchar (200)

set @parameter ='1_2_3|4_5'

SELECT ss=isnull(MAX(CASE c.itemnumber WHEN 1 THEN c.item END), 0)

,col=isnull(MAX(CASE c.itemnumber WHEN 2 THEN c.item END), 0)

,col1=isnull(MAX(CASE c.itemnumber WHEN 3 THEN c.item END), 0)

FROM (SELECT @parameter) a(parameter)

CROSS APPLY dbo.DelimitedSplit8k(parameter, '|') b

CROSS APPLY dbo.DelimitedSplit8k(item, '_') c

GROUP BY b.ItemNumber

_______________________________________________________________

Need help? Help us help you.

Read the article at http://www.sqlservercentral.com/articles/Best+Practices/61537/ for best practices on asking questions.

Need to split a string? Try Jeff Modens splitter http://www.sqlservercentral.com/articles/Tally+Table/72993/.

Cross Tabs and Pivots, Part 1 – Converting Rows to Columns - http://www.sqlservercentral.com/articles/T-SQL/63681/
Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs - http://www.sqlservercentral.com/articles/Crosstab/65048/
Understanding and Using APPLY (Part 1) - http://www.sqlservercentral.com/articles/APPLY/69953/
Understanding and Using APPLY (Part 2) - http://www.sqlservercentral.com/articles/APPLY/69954/

Sean Lange SSC Guru Points: 286590 More actions · Answer 4

More importantly than getting the desired output....do you understand what that function does? Can you explain it somebody else? Keep in mind that YOU are the person who has to support this code at 3am when the phone rings.

_______________________________________________________________

Need help? Help us help you.

Read the article at http://www.sqlservercentral.com/articles/Best+Practices/61537/ for best practices on asking questions.

Need to split a string? Try Jeff Modens splitter http://www.sqlservercentral.com/articles/Tally+Table/72993/.

Cross Tabs and Pivots, Part 1 – Converting Rows to Columns - http://www.sqlservercentral.com/articles/T-SQL/63681/
Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs - http://www.sqlservercentral.com/articles/Crosstab/65048/
Understanding and Using APPLY (Part 1) - http://www.sqlservercentral.com/articles/APPLY/69953/
Understanding and Using APPLY (Part 2) - http://www.sqlservercentral.com/articles/APPLY/69954/

Sivaganesh Tamilvendhan Hall of Fame Points: 3498 More actions · Answer 5

Sivaganesh Tamilvendhan

Hall of Fame

Points: 3498

August 28, 2012 at 11:04 pm

#1531199

thanks

Sean Lange