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Calculating date

  • September 6, 2012 at 5:02 pm

    #267364

    I have a table as follows

    Logtable

    ID Date User action

    1 8/6/2012 12:10:36 A Something

    2 8/6/2012 12:09:34 A Something

    3 8/6/2012 12:09:33 A Something

    how can i select 8/6/2012 12:10:33 in this table instead of the other two dates for the user A with action something and not with the ID i need to compare the date and get the first time logged into the table

  • September 6, 2012 at 7:03 pm

    #1534809

    First item the time you say you need to pick is

    8/6/2012 12:10:33

    that time does NOT exist in the data you have listed. That said is this what you require ?

    CREATE TABLE #T(ID INT, D DATETIME,U VARCHAR(5),Ac VARCHAR(20))

    INSERT INTO #T

    SELECT 1, '8/6/2012 12:10:36','A','Something' UNION ALL

    SELECT 2, '8/6/2012 12:09:34','A','Something' UNION ALL

    SELECT 3, '8/6/2012 12:09:33','A','Something'

    SELECT ID,D,U,Ac FROM #T WHERE D IN (SELECT MIN(D) FROM #t)

    Result:

    IDD U Ac

    32012-08-06 12:09:33.000ASomething

    If everything seems to be going well, you have obviously overlooked something.

    Ron

    Please help us, help you -before posting a question please read[/url]
    Before posting a performance problem please read[/url]

  • September 6, 2012 at 7:03 pm

    #1534810

    SQLTestUser (9/6/2012)

    I have a table as follows

    Logtable

    ID Date User action

    1 8/6/2012 12:10:36 A Something

    2 8/6/2012 12:09:34 A Something

    3 8/6/2012 12:09:33 A Something

    how can i select 8/6/2012 12:10:33 in this table instead of the other two dates for the user A with action something and not with the ID i need to compare the date and get the first time logged into the table

    Normally the forum requests that you provide DDL and sample data in a consumable format like this:

    DECLARE @t TABLE (ID INT, Date DATETIME, [User] VARCHAR(10), Action VARCHAR(10))

    INSERT INTO @t

    SELECT 1, '8/6/2012 12:10:36', 'A', 'Something'

    UNION ALL SELECT 2, '8/6/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 3, '8/6/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 4, '8/6/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 5, '8/6/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 6, '8/6/2012 12:09:33', 'B', 'Something'

    UNION ALL SELECT 7, '8/7/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 8, '8/7/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 9, '8/7/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 10, '8/7/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 11, '8/7/2012 12:09:33', 'B', 'Something'

    This then politely allows our volunteer members to focus on a solution:

    -- First login by user

    ;WITH FirstLogin AS (

    SELECT ID, Date, [User], Action

    ,rn=ROW_NUMBER() OVER (PARTITION BY [User] ORDER BY Date)

    FROM @t)

    SELECT ID, Date, [User], Action

    FROM FirstLogin

    WHERE rn=1

    -- First login by user by date

    ;WITH FirstLogin AS (

    SELECT ID, Date, [User], Action

    ,rn=ROW_NUMBER() OVER (

    PARTITION BY [User], DATEADD(d, DATEDIFF(d, 0, Date), 0) ORDER BY Date)

    FROM @t)

    SELECT ID, Date, [User], Action

    FROM FirstLogin

    WHERE rn=1

    My mantra: No loops! No CURSORs! No RBAR! Hoo-uh![/I]

    My thought question: Have you ever been told that your query runs too fast?

    My advice:
    INDEXing a poor-performing query is like putting sugar on cat food. Yeah, it probably tastes better but are you sure you want to eat it?
    The path of least resistance can be a slippery slope. Take care that fixing your fixes of fixes doesn't snowball and end up costing you more than fixing the root cause would have in the first place.

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  • September 6, 2012 at 7:34 pm

    #1534816

    thanks for the reply i also have to make sure that the date is between last two days or 10 days as

    ID Date User action

    1 8/4/2012 12:10:36 A Something

    2 8/4/2012 12:09:34 A Something

    3 8/4/2012 12:09:33 A Something

    SELECT *

    FROM Log

    WHERE (time IN

    (SELECT MIN(Time)

    FROM Log AS T))

    AND (DATEDIFF(d, T.Time, GETDATE()) = 2)

    and aciton = 'something' but this doesnot result in anything

    so that the result is displayed for everything that is the min date for a particular action

  • September 6, 2012 at 8:42 pm

    #1534824

    SQLTestUser (9/6/2012)

    thanks for the reply i also have to make sure that the date is between last two days or 10 days as

    ID Date User action

    1 8/4/2012 12:10:36 A Something

    2 8/4/2012 12:09:34 A Something

    3 8/4/2012 12:09:33 A Something

    SELECT *

    FROM Log

    WHERE (time IN

    (SELECT MIN(Time)

    FROM Log AS T))

    AND (DATEDIFF(d, T.Time, GETDATE()) = 2)

    and aciton = 'something' but this doesnot result in anything

    so that the result is displayed for everything that is the min date for a particular action

    BWAAA-HAAA!!! Do you really expect 8/4/2012 to be just 2 days ago with today being 9/6/2012? 😀

    Shifting gears, folks really do like to prove their code before posting it and, as a result, you get a better answer quicker. To help us help you more quickly, we need your data, as simple as it is, in a readily consumable format. Please read the first link in my signature line below for an easy way to do that in the future.

    --Jeff Moden

    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

    Change is inevitable... Change for the better is not.

    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)

  • September 7, 2012 at 5:58 am

    #1535019

    You can try the same as Mr. Ten Centuries suggested with some modification

    create TABLE t1 (ID INT, Date DATETIME, [User] VARCHAR(10), Action VARCHAR(10))

    INSERT INTO t1

    SELECT 22, '8/16/2012 12:10:36', 'A', 'Something'

    UNION ALL SELECT 2, '8/6/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 3, '8/6/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 4, '8/6/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 5, '8/6/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 6, '8/6/2012 12:09:33', 'B', 'Something'

    UNION ALL SELECT 7, '8/7/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 8, '8/7/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 9, '8/7/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 10, '8/7/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 11, '8/7/2012 12:09:33', 'B', 'Something'

    UNION ALL SELECT 12, '9/7/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 13, '9/5/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 14, '9/5/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 15, '9/3/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 16, '9/3/2012 12:09:33', 'B', 'Something'

    UNION ALL SELECT 17, '9/3/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 18, '9/3/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 19, '8/17/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 20, '8/17/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 21, '8/17/2012 12:09:33', 'B', 'Something'

    UNION ALL SELECT 22, '8/16/2012 12:10:36', 'A', 'Something'

    -- First login by user by date

    ;WITH FirstLogin AS (

    SELECT ID, Date, [User], Action

    ,rn=ROW_NUMBER() OVER (

    PARTITION BY [User], DATEADD(d, DATEDIFF(d, 0, Date), 0) ORDER BY Date)

    FROM t1)

    SELECT ID, Date, [User], Action

    FROM FirstLogin

    WHERE rn=1 and Date > DATEADD(DD,-2,GETDATE()) order by Date desc -- FOR 2 Days

    --WHERE rn=1 and Date > DATEADD(DD,-10,GETDATE()) order by Date desc -- FOR 10 Days

    --WHERE rn=1 and Date > DATEADD(DD,-20,GETDATE()) order by Date desc -- FOR 20 Days

    You can go ahead with the changing the number days at your concern here I considered as 2.

    Sumit Rastogi;-)

  • September 8, 2012 at 7:42 pm

    #1535442

    I don't know if i am missing something. :hehe:

    But we should be able to achieve desired result(Last 10 Days) via below

    Select user,min(action)

    from logtable

    where action >=convert(varchar(11,getdate()-10,106)

    group by User

    Or if you want to get first log in time for each day in last 10 days

    Select

    user,cast(convert(varchar(11),Action,106) as datetime) as [Date],min(Action) as [Action Time] from logtable where Action>=convert(varchar(11,getdate()-10,106)

    group by cast(convert(varchar(11,Action,106) as datetime), User

  • September 14, 2012 at 6:47 am

    #1537785

    This query will not give correct output in this case

    create TABLE t1 (ID INT, Date DATETIME, [User] VARCHAR(10), Action VARCHAR(10))

    INSERT INTO t1

    SELECT 22, '8/16/2012 12:10:36', 'A', 'Something'

    UNION ALL SELECT 2, '8/6/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 3, '8/6/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 4, '8/6/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 5, '8/6/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 6, '8/6/2012 12:09:33', 'B', 'Something'

    UNION ALL SELECT 7, '8/7/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 8, '8/7/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 9, '8/7/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 10, '8/7/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 11, '8/7/2012 12:09:33', 'B', 'Something'

    UNION ALL SELECT 12, '9/14/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 13, '9/6/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 14, '9/5/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 15, '9/3/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 16, '9/9/2012 12:09:33', 'B', 'Something'

    UNION ALL SELECT 17, '9/3/2012 12:09:34', 'A', 'Something'

    UNION ALL SELECT 18, '9/3/2012 12:09:33', 'A', 'Something'

    UNION ALL SELECT 19, '8/17/2012 12:10:36', 'B', 'Something'

    UNION ALL SELECT 20, '9/13/2012 12:09:34', 'B', 'Something'

    UNION ALL SELECT 21, '9/14/2012 12:09:33', 'B', 'Something'

    UNION ALL SELECT 22, '8/16/2012 12:10:36', 'A', 'Something'

    Try this one:

    ;WITH FirstLogin AS (

    SELECT ID, Date, [User], Action,DATEADD(d, DATEDIFF(d, 0, Date), 0) [D]

    ,rn=ROW_NUMBER() OVER (

    PARTITION BY [User] ORDER BY Date)

    FROM t1 WHERE Date > DATEADD(DD,-2,GETDATE())

    )

    SELECT ID, Date, [User], Action

    FROM FirstLogin

    WHERE rn=1 order by Date desc

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