July 18, 2014 at 9:06 am
I am sorry, Chris for not mentioning your name. Thanks for your support
July 18, 2014 at 9:10 am
pmadhavapeddi22 (7/18/2014)
I am sorry, Chris for not mentioning your name. Thanks for your support
Happy Friday ๐
For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden
July 18, 2014 at 9:14 am
OP...what is the correct answer for the count of "repetitive days"...seems my answer is different than the others ???
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July 21, 2014 at 2:34 am
Livingston, I took the logic What you have mentioned, I took the count of those days which are matching in both assgn_dtm and complet_dtm and then deducting those from sum of all days
This has to be implemented in another query, so I have used a function to return the diff of days
Thank you all for your time and support
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