Alphanumeric number generation

Question

Alphanumeric number generation

Minnu

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Points: 6451
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October 8, 2012 at 5:38 am

#282710

Hi,
I need to write a SQL query to print the following aphanumberic sequence in SQL 2008.
0001, 0002, ... , 0009, 000A, ... , 000Z, ... , 0010, 0011, ... , 001A, ... and so on till... , ZZZZ
all characters should be in UPPERCASE.
Please Help me...
Thanks in advance

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ChrisM@Work SSC Guru Points: 186127 More actions · Answer 1

Forgive me if I'm mistaken, but all of your posts look like homework. What have you tried so far?

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

Minnu SSCertifiable Points: 6451 More actions · Answer 2

Hi,

not exactly like home work, as per my requirement only am posting.

i've tried below code, but it is generating only number.

WITH Sequence ( SeqNo) as

(

SELECT 1

UNION ALL

SELECT SeqNo + 1

FROM Sequence

WHERE SeqNo < 1000

)

SELECT TOP 1000 * FROM Sequence

OPTION ( MAXRECURSION 0);

GO

please help me......

ChrisM@Work SSC Guru Points: 186127 More actions · Answer 3

Use table constructor to generate your primary sequence, within a CTE. Then run a select from it, joined to itself 3 times (giving 4 references total in the FROM list). They can be CROSS JOINS or old fashioned comma joins. It works just fine. Have a try, post back if you are unsure.

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

Minnu SSCertifiable Points: 6451 More actions · Answer 4

Below code is working in 'Oracle'

i need same output in sql.....

with digits as

( select n, chr(mod(n,36)+case when mod(n,36) < 10 then 48 else 55 end) d

from (Select rownum-1 as n from dual connect by level < 37)

)

select d0.n*36*36*36*36 + d1.n*36*36*36 + d2.n*36*36 + d3.n*36 + d4.n, d0.d||d1.d||d2.d||d3.d||d4.d

from digits d0,digits d1, digits d2, digits d3, digits d4

Plz

Cadavre SSC-Forever Points: 41690 More actions · Answer 5

Skanda (10/8/2012)
Hi,
not exactly like home work, as per my requirement only am posting.
i've tried below code, but it is generating only number.
WITH Sequence ( SeqNo) as
(
SELECT 1
UNION ALL
SELECT SeqNo + 1
FROM Sequence
WHERE SeqNo < 1000
)
SELECT TOP 1000 * FROM Sequence
OPTION ( MAXRECURSION 0);
GO
please help me......

You're looking at the top 1000 in your query, have you thought about how many rows there will actually be?

You have 36 characters in total for each digit (0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z). So we're looking at 36*36*36*36 == 1,679,616 rows.

Forever trying to learn
My blog - http://www.cadavre.co.uk/
For better, quicker answers on T-SQL questions, click on the following...http://www.sqlservercentral.com/articles/Best+Practices/61537/
For better, quicker answers on SQL Server performance related questions, click on the following...http://www.sqlservercentral.com/articles/SQLServerCentral/66909/

Cadavre SSC-Forever Points: 41690 More actions · Answer 6

Skanda (10/8/2012)
Below code is working in 'Oracle'
i need same output in sql.....
with digits as
( select n, chr(mod(n,36)+case when mod(n,36) < 10 then 48 else 55 end) d
from (Select rownum-1 as n from dual connect by level < 37)
)
select d0.n*36*36*36*36 + d1.n*36*36*36 + d2.n*36*36 + d3.n*36 + d4.n, d0.d||d1.d||d2.d||d3.d||d4.d
from digits d0,digits d1, digits d2, digits d3, digits d4
Plz

Chris covered how in his post, did you try it?

SELECT a.Chr+b.Chr+c.Chr+d.Chr

FROM (VALUES('0'),('1'),('2'),('3'),('4'),('5'),('6'),

('7'),('8'),('9'),('A'),('B'),('C'),('D'),

('E'),('F'),('G'),('H'),('I'),('J'),('K'),

('L'),('M'),('N'),('O'),('P'),('Q'),('R'),

('S'),('T'),('U'),('V'),('W'),('X'),('Y'),

('Z')

)a(Chr)

CROSS JOIN (VALUES('0'),('1'),('2'),('3'),('4'),('5'),('6'),

('7'),('8'),('9'),('A'),('B'),('C'),('D'),

('E'),('F'),('G'),('H'),('I'),('J'),('K'),

('L'),('M'),('N'),('O'),('P'),('Q'),('R'),

('S'),('T'),('U'),('V'),('W'),('X'),('Y'),

('Z')

)b(Chr)

CROSS JOIN (VALUES('0'),('1'),('2'),('3'),('4'),('5'),('6'),

('7'),('8'),('9'),('A'),('B'),('C'),('D'),

('E'),('F'),('G'),('H'),('I'),('J'),('K'),

('L'),('M'),('N'),('O'),('P'),('Q'),('R'),

('S'),('T'),('U'),('V'),('W'),('X'),('Y'),

('Z')

)c(Chr)

CROSS JOIN (VALUES('0'),('1'),('2'),('3'),('4'),('5'),('6'),

('7'),('8'),('9'),('A'),('B'),('C'),('D'),

('E'),('F'),('G'),('H'),('I'),('J'),('K'),

('L'),('M'),('N'),('O'),('P'),('Q'),('R'),

('S'),('T'),('U'),('V'),('W'),('X'),('Y'),

('Z')

)d(Chr)

ORDER BY a.Chr, b.Chr, c.Chr, d.Chr;

Forever trying to learn
My blog - http://www.cadavre.co.uk/
For better, quicker answers on T-SQL questions, click on the following...http://www.sqlservercentral.com/articles/Best+Practices/61537/
For better, quicker answers on SQL Server performance related questions, click on the following...http://www.sqlservercentral.com/articles/SQLServerCentral/66909/

Minnu SSCertifiable Points: 6451 More actions · Answer 7

in query trying for 1000,

but i need max.

if it is more than 36*36*36*36, it helps me a lot...

Minnu SSCertifiable Points: 6451 More actions · Answer 8

Thank U Boss,

It is looking great...

but i need every record should have a numeric and alpabet,

in present code, some records are only alphabetic....

ChrisM@Work SSC Guru Points: 186127 More actions · Answer 9

Skanda (10/8/2012)
Hi,
I need to write a SQL query to print the following aphanumberic sequence in SQL 2008.
0001, 0002, ... , 0009, 000A, ... , 000Z, ... , 0010, 0011, ... , 001A, ... and so on till... , ZZZZ
all characters should be in UPPERCASE.
Please Help me...
Thanks in advance

Here's a TSQL equivalent of the Oracle CTE:

SELECT

n,

CHAR(n + CASE WHEN n < 10 THEN 48 ELSE 55 END)

FROM (SELECT TOP(36) n = ROW_NUMBER() OVER (ORDER BY (SELECT NULL))-1 FROM sys.columns a, sys.columns b) t

ORDER BY n

Can you figure it out from here?

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

Cadavre SSC-Forever Points: 41690 More actions · Answer 10

Skanda (10/8/2012)
Thank U Boss,
It is looking great...
but i need every record should have a numeric and alpabet,
in present code, some records are only alphabetic....

In your original post, you said: -

Skanda (10/8/2012)
0001, 0002, ... , 0009, 000A, ... , 000Z, ... , 0010, 0011, ... , 001A, ... and so on till... , ZZZZ

"ZZZZ" doesn't have numeric values.

Forever trying to learn
My blog - http://www.cadavre.co.uk/
For better, quicker answers on T-SQL questions, click on the following...http://www.sqlservercentral.com/articles/Best+Practices/61537/
For better, quicker answers on SQL Server performance related questions, click on the following...http://www.sqlservercentral.com/articles/SQLServerCentral/66909/

Eugene Elutin SSC Guru Points: 59322 More actions · Answer 11

Cadavre (10/8/2012)
Skanda (10/8/2012)
Thank U Boss,
It is looking great...
but i need every record should have a numeric and alpabet,
in present code, some records are only alphabetic....
In your original post, you said: -
Skanda (10/8/2012)
0001, 0002, ... , 0009, 000A, ... , 000Z, ... , 0010, 0011, ... , 001A, ... and so on till... , ZZZZ
"ZZZZ" doesn't have numeric values.

And "0001, 0002, ... , 0009..." have no alpha characters...

I guess the method I've offered in the following thread might help you:

http://www.sqlservercentral.com/Forums/Topic1267659-391-1.aspx

_____________________________________________
"The only true wisdom is in knowing you know nothing"
"O skol'ko nam otkrytiy chudnyh prevnosit microsofta duh!":-D
(So many miracle inventions provided by MS to us...)

How to post your question to get the best and quick help[/url]

Jeff Moden SSC Guru Points: 1004318 More actions · Answer 12

I wonder how many 3 and 4 letter swear words such a proccess will actually spell out.

I strongly recommend not using incrementing alpha-numerics for just such a reason but if you do, you really need to avoid the use of vowels at the very least.

--Jeff Moden

RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

Change is inevitable... Change for the better is not.

Helpful Links:
How to post code problems
How to Post Performance Problems
Create a Tally Function (fnTally)

Eugene Elutin SSC Guru Points: 59322 More actions · Answer 13

Jeff Moden (10/27/2012)
I wonder how many 3 and 4 letter swear words such a proccess will actually spell out...

Actually it depends how you take it, at least some of them will be easy to remember :-D.

By the way, English as a language is not very rich with such words in compare with some other languages (eg. world-champion in this business: Russian :hehe:)

_____________________________________________
"The only true wisdom is in knowing you know nothing"
"O skol'ko nam otkrytiy chudnyh prevnosit microsofta duh!":-D
(So many miracle inventions provided by MS to us...)

How to post your question to get the best and quick help[/url]

Jeff Moden SSC Guru Points: 1004318 More actions · Answer 14

Eugene Elutin (10/29/2012)
Jeff Moden (10/27/2012)
I wonder how many 3 and 4 letter swear words such a proccess will actually spell out...
Actually it depends how you take it, at least some of them will be easy to remember :-D.
By the way, English as a language is not very rich with such words in compare with some other languages (eg. world-champion in this business: Russian :hehe:)

That's why we shouldn't be Russian to use incrementing Alpha-Numerics. 😛

--Jeff Moden

RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

Change is inevitable... Change for the better is not.

Helpful Links:
How to post code problems
How to Post Performance Problems
Create a Tally Function (fnTally)