November 2, 2022 at 4:13 am
I need to add a single quote in each of the alternate characters. The input string could be a variable length.
As an example:
Input String: 5,1,6,1,69,1
output: '5',1,'6',1,'69',1
Input String: 5,1,6,1,3,2,5,3,69,1
output: '5',1,'6',1,'3',2,'5',3,'69',1
November 2, 2022 at 3:33 pm
drop table if exists #some_table;
go
create table #some_table (
input_string varchar(200) not null);
insert #some_table(input_string) values
('5,1,6,1,69,1'),
('5,1,6,1,3,2,5,3,69,1');
select string_agg(iif((ss.ordinal-1)%2=0, concat('''', ss.[value], ''''), ss.[value]), ',')
within group (order by ss.ordinal) [output]
from #some_table st
cross apply string_split(st.input_string, ',', 1) ss
group by st.input_string;
Aus dem Paradies, das Cantor uns geschaffen, soll uns niemand vertreiben können
November 2, 2022 at 3:49 pm
The enable_ordinal argument for STRING_SPLIT is not implemented in 2019.
The absence of evidence is not evidence of absence.
Martin Rees
You can lead a horse to water, but a pencil must be lead.
Stan Laurel
November 2, 2022 at 3:59 pm
Does this work? I don't know if there will ever be spaces, but I removed them anyway.
DECLARE @InputString VARCHAR(1000) = '5, 1,6, 1,69,1, 123456, 9'
SELECT REPLACE(CONCAT('''', REPLACE(@InputString, ',', ''','''), ''''), ' ', '')
In case of preceding or trailing commas.
DECLARE @InputString VARCHAR(1000) = '5, 1,6, 1,69,1, 123456, 9,'
SELECT REPLACE(CONCAT('''', REPLACE(TRIM(',' FROM @InputString), ',', ''','''), ''''), ' ', '')
November 2, 2022 at 4:11 pm
The enable_ordinal argument for STRING_SPLIT is not implemented in 2019.
It's true. It's available in Azure SQL compatibility level 150 (and above) and SQL Server 2022. There are alternatives such as:
Aus dem Paradies, das Cantor uns geschaffen, soll uns niemand vertreiben können
November 2, 2022 at 6:53 pm
How about a cte?
drop table if exists #some_table;
go
create table #some_table (
input_string varchar(200) not null);
insert #some_table(input_string) values
('5,1,6,1,69,1'),
('5,1,6,1,3,2,5,3,69,1'),
('5 ,2,36,1,69,1')
;
;with cte as (select input_string, case when RowNum %2 = 0 then [value] else Concat('''',[value],'''') end as NewValue from (
select input_string, ltrim(rtrim([value])) as [Value], row_number() over (partition by st.input_string order by st.input_string) as RowNum
from #some_table st
cross apply string_split(st.input_string, ',') ss) x)
SELECT input_string,
STUFF(
( SELECT ',' + NewValue
FROM cte t2
WHERE t1.input_string=t2.input_string
FOR XML PATH('')
),
1,
1,''
) AS NewValue
FROM cte t1
GROUP BY input_String
For better, quicker answers, click on the following...
http://www.sqlservercentral.com/articles/Best+Practices/61537/
For better answers on performance questions, click on the following...
http://www.sqlservercentral.com/articles/SQLServerCentral/66909/
November 2, 2022 at 10:44 pm
I need to add a single quote in each of the alternate characters. The input string could be a variable length.
As an example:
Input String: 5,1,6,1,69,1
output: '5',1,'6',1,'69',1
Input String: 5,1,6,1,3,2,5,3,69,1
output: '5',1,'6',1,'3',2,'5',3,'69',1
If you explain why this strange requirement exists, I'll provide the exact code necessary to accomplish it.
--Jeff Moden
Change is inevitable... Change for the better is not.
November 2, 2022 at 10:57 pm
skmoh2 wrote:I need to add a single quote in each of the alternate characters. The input string could be a variable length.
As an example:
Input String: 5,1,6,1,69,1
output: '5',1,'6',1,'69',1
Input String: 5,1,6,1,3,2,5,3,69,1
output: '5',1,'6',1,'3',2,'5',3,'69',1
If you explain why this strange requirement exists, I'll provide the exact code necessary to accomplish it.
My guess is that when you put a single quote in front of a number in an Excel cell then the cell is formatted as text not a number.
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