TSQL Challenge 48 - Parse and evaluate Arithmetic Expressions using TS
This challenge is to parse and evaluate arithmetic expressions using TSQL.
2011-01-24
2,292 reads
This challenge is to parse and evaluate arithmetic expressions using TSQL.
2011-01-24
2,292 reads
A table contains the list of modifications made to each card. Your job is to write a query that shows the first number, current number (most recent) and the number of changes made.
2011-01-10
954 reads
This challenge is a slightly enhanced version of the ‘remove leading zeros’ problem
2010-12-27
1,726 reads
This challenge involves evaluating mathematical expressions presented using Roman Numerals and return the result of each expression.
2010-12-13
1,679 reads
The first part of your job is to identify the unique color combinations of products and the second part is to identify the products that have the given color combination.
2010-11-29
1,361 reads
This challenge involves writing a logic to identify incomplete segments and missing elements in an electronic data integration file exchanged between two applications.
2010-11-16
858 reads
This challenge involves writing a logic to change the column position of values in the output based on the presence and absence of other values on each output row.
2010-11-01
2,841 reads
This challenge involves extracting email addresses from a table that contains text data downloaded from various websites.
2010-10-18
2,256 reads
This challenge involves converting numeric values from binary format to hexadecimal format.
2010-10-04
1,652 reads
This challenge is related to an inventory management application where your job is to calculate the profitability by item (cost v/s sales) using First-In-First-Out (FIFO) processing method.
2010-09-20
2,137 reads
By Steve Jones
It was neat to stumble on this in the book, a piece by me,...
Forgive me for the title. Mentally I’m 12. When I started my current day...
By Steve Jones
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Comments posted to this topic are about the item The String Distance I
In SQL Server 2025, what is returned by this code:
SELECT EDIT_DISTANCE('Steve', 'Stan')
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