What Have You Done Lately Outside of Work?
Today Steve asks the question about what you do outside of work to advance your career.
2023-08-11
123 reads
Today Steve asks the question about what you do outside of work to advance your career.
2023-08-11
123 reads
Most of us want more autonomy at work, but it isn't given out without effort. Today Andy Warren has a few thoughts on how to get more freedom from your boss.
2023-07-24
133 reads
2023-07-12
150 reads
If you found out you were being laid off, would you be ready? Steve thinks you should be lightly planning for this to happen.
2023-06-30
157 reads
A lot of today’s questions from https://pollgab.com/room/brento have a common theme, but it’s just a coincidence. Listen to the answers.
2023-06-26
2023-06-24
165 reads
The highly skilled people are changing and getting jobs. A recent report notes this is of concern to executives and hiring practices may be changing. Steve has a few hints for how you can grow your own career and find new opportunities.
2023-06-19
231 reads
2023-06-09
157 reads
2023-05-05
118 reads
There have been a lot of layoffs in the last year. Steve has some empathy for both those let go and those that remain. He also reminds us to manage our own careers.
2023-04-28
162 reads
By James Serra
I’m honored to be hosting T-SQL Tuesday — edition #192. For those who may...
By Vinay Thakur
Continuing from Day 2 , we learned introduction on Generative AI and Agentic AI,...
Quite the title, so let me set the stage first. You have an Azure...
Comments posted to this topic are about the item Rollback vs. Roll Forward
Comments posted to this topic are about the item Foreign Keys - Foes or...
Comments posted to this topic are about the item Fun with JSON I
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT *
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t; See possible answers