2020-07-31
453 reads
2020-07-31
453 reads
With the new labeling and classificiation options in SQL Server, there might be a need to remove these labels before deploying the database.
2020-07-31 (first published: 2018-12-20)
4,836 reads
The workplace is certainly changing with the COVID-19 pandemic. Steve shares a few learnings from Microsoft's work from home experiment.
2020-07-31
123 reads
2020-07-30
76 reads
I don’t do a lot of team builds in Azure DevOps, but I constantly use it for demos. However, I’m often experimenting with things and I break builds regularly....
2020-07-30 (first published: 2020-07-20)
316 reads
I’ve started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-07-30
12 reads
2020-07-30
593 reads
2020-07-29
517 reads
I’ve started to add a daily coping tip to the SQLServerCentral newsletter and to the Community Circle, which is helping me deal with the issues in the world. I’m...
2020-07-29
20 reads
Learning to adapt the way we work is important for advancing our career, but this can be harder than we expect.
2020-07-29
148 reads
By Brian Kelley
I will be leading an in-person Certified Information Systems Auditor (CISA) exam prep class...
EightKB is back again for 2026! The biggest online SQL Server internals conference is...
By HeyMo0sh
Working in DevOps long enough teaches you two universal truths: That’s exactly why I...
Comments posted to this topic are about the item Fun with JSON II
Comments posted to this topic are about the item Changing Data Types
Comments posted to this topic are about the item Answering Questions On Dropped Columns
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
t2.*
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t1
CROSS APPLY OPENJSON(t1.value) t2; See possible answers