Notes from SQLSaturday in Oregon Nov 16, 2013
I wanted to take time to thank our sponsors, speakers and volunteers for making #sqlsat265 a big success. Over 400...
2013-11-21
557 reads
Recruiting for “Women In Technology” panelist for Oregon SQLSaturay Oct 8th, 2011
We are recruiting panelists for a “Women in Technology” discussion at SQLSaturday Oregon. SQLSaturday is an all-day free training event...
2011-08-01
547 reads
Speaking at SQL Saturday #68 on Women in Technology
I am excited that I get to speak at SQL Saturday #68 on April 9. If you live close to...
2011-03-29
546 reads
Silent Install
A few weeks a go I presented at OSQL-D in Portland, OR, and a lot of people ask me if...
2011-01-29
2,332 reads
The Events that Brought Me Here
1st event: I am here because my father wanted to be reunited with his family. He also hoped that his...
2010-02-04
678 reads
transactional replication:initialize with backup
I spend this weekend playing with transaction replication and try to set it up so that I don't have to...
2009-12-06
1,047 reads
a simple joint that makes you think twice
I was reading Two Minute SQL Server Stumpers a few weeks ago and this qustion still sticks in my head. ...
2009-12-01
571 reads
Blogs
T-SQL Tuesday #180: Good enough is perfect Roundup
This month, I prompted bloggers to discuss whether good enough is perfect. Thank you to all...
Using SQL Compare with Read-only Access
By Steve Jones
Recently a customer asked if SQL Compare and SQL Data Compare can be used...
Forums
how can i tell if our db2 driver is ms or ibm or other?
i see this in the definition of a linked server on our wh sql...
normal role member to be able to view list of other role members in his DB
Is this even possible ? Tried with grant but to no avail. [sys].[database_role_members] and...
Stairway to Snowflake Level 5 - Using Snowflake with SnowSQL and Visual Studio Code
Comments posted to this topic are about the item Stairway to Snowflake Level 5...
Question of the Day
A Strange Result
What does this code return in SSMS 20 from SQL Server 2019?
select '|' + CHAR(0)+'abc' + '|';See possible answers