Find Largest size Tables in a Database
To find a list of Tables (User or System tables)according to their size.
2013-01-02 (first published: 2008-07-10)
4,283 reads
To find a list of Tables (User or System tables)according to their size.
2013-01-02 (first published: 2008-07-10)
4,283 reads
This Function is written to split Multivalued Parameter passed by Reporting Services 2005.
2012-07-16 (first published: 2007-08-01)
2,785 reads
2009-10-05
4,036 reads
2008-08-15
6,034 reads
This is very simple query to find Nth Maximum number from a Table. For example, using this query, we can identify the 5th, 8th or Nth highest paid employee of an organization.
2007-09-06 (first published: 2007-04-29)
960 reads
I wrote this script to compare record counts between a live database and a restored copy to test backups, I thought people might find it useful. What You need is to just copy the script and run it against your database.
2007-08-21
1,411 reads
This is a generalised Function that will return a String in Proper Case [Camel Case]. Means Afetr every space, first later will be in UPPER Case.Example:Input String: 'microSoft sql server'Output String: 'Microsoft Sql Server'
2007-05-09 (first published: 2007-04-19)
19,860 reads
This function will return you the month-end date. Input parameter may be any date of that month for which you want to calculate month-end.Example:Input: '2-20-2004' Output: '2-29-2004'Input: '2-15-2004' Output: '2-29-2004'Input: '3-20-2004' Output: '3-31-2004'Input: '3-30-2004' Output: '3-31-2004'
2007-05-08 (first published: 2007-04-19)
1,316 reads
This month, I prompted bloggers to discuss whether good enough is perfect. Thank you to all...
By Steve Jones
Recently a customer asked if SQL Compare and SQL Data Compare can be used...
i see this in the definition of a linked server on our wh sql...
Is this even possible ? Tried with grant but to no avail. [sys].[database_role_members] and...
Comments posted to this topic are about the item Stairway to Snowflake Level 5...
What does this code return in SSMS 20 from SQL Server 2019?
select '|' + CHAR(0)+'abc' + '|';See possible answers