An interview with Jeff Moden: Exceptional DBA of 2011 and natural helper
Jeff Moden has been elected as the Exceptional DBA of 2011. Here, Jeff talks to Bob Cramblitt about the life of an exeptional DBA.
2011-09-21
1,967 reads
Jeff Moden has been elected as the Exceptional DBA of 2011. Here, Jeff talks to Bob Cramblitt about the life of an exeptional DBA.
2011-09-21
1,967 reads
We are pleased to announce that Jeff Moden has been elected by judges and the SQL Server community as the Exceptional DBA of 2011.
2011-09-14
1,287 reads
Nominations for The Exceptional DBA of 2010 open today, giving database administrators around the world the chance to be recognized for service to their employers, the SQL Server community, and the IT industry at large.
2010-05-04
853 reads
Josef Richberg is an exceptional person: The Judges of the Exceptional DBA Award were quickly proved right in their decision to choose him, when he subsequently showed extraordinary resilience and determination in the face of an unexpected diagnosis of cancer. His determination to deal positively with a difficult life-event is surely a source of inspiration to all of us.
2009-11-17
1,103 reads
Josef Richberg, a DBA with HarperCollins Publishers, has been selected by judges and the DBA community as winner of 2009’s Exceptional DBA Awards, sponsored by Red Gate Software. Freelance writer Bob Cramblitt spoke to Richberg about the role of the DBA and the importance of sharing knowledge with the community.
2009-09-03
2,000 reads
By Steve Jones
This is my last week of the year working (I guess I come back...
By Steve Jones
This is my last week of the year working (I guess I come back...
I recently read the book Agile Data Warehouse Design – Collaborative Dimensional Modeling, from...
I have an ADF pipeline that copies Files from source to destination. Both Source...
Comments posted to this topic are about the item Function Defaults
I have created this function in SQL Server 2022:
CREATE FUNCTION dbo.AddInt (@one INT, @two INT = 1) RETURNS INT AS BEGIN RETURN @one + @two ENDHow can I call this and invoke the default value for @two? See possible answers