Notes From the January 2014 MagicPass Meeting
I went 30 miles south last night for the first meeting of the year. Extra good night because I was...
2014-01-16
483 reads
I went 30 miles south last night for the first meeting of the year. Extra good night because I was...
2014-01-16
483 reads
This past weekend I was doing some early Spring cleaning and decided it was time to throw out two old...
2014-01-15
626 reads
Here are some of the questions I ask when someone is thinking about running for the Board:
Are you eligible? Read...
2014-01-15
541 reads
Something you have and something you know – that’s the heart of two-factor, sometimes called multi-factor, authentication. RSA was for years...
2014-01-15 (first published: 2014-01-09)
6,319 reads
I was a bit sad to see that Google bought Nest. I like upstarts that see a problem and solve...
2014-01-14
626 reads
I know it’s only January, but if you’re at all considering being a candidate you need to get going now....
2014-01-14
433 reads
First meeting of the year with Bradley Ball presenting Locking, Blocking, Latches, Deadlocks, and Spinlocks. Let them know you’ll be...
2014-01-13
659 reads
Let’s say you’ve decided to run, good! What do you do next? I’m not going to give you a blueprint...
2014-01-10
387 reads
I saw a discussion on Twitter yesterday where Kendal Van Dyke referenced the SQLSaturday wiki as a resource, I thought...
2014-01-10
380 reads
There was a blurb in the Connector today about an eligibility change for voting. The “change” is a requirement to...
2014-01-08
380 reads
By Steve Jones
I missed blogging yesterday as I was on stage/backstage for quite a bit of...
By Brian Kelley
A common theme in the PASS Summits I've attended is community and that's definitely...
By Chris Yates
I am excited to cover the Microsoft Keynote on Day 2: Redgate Keynote: Simplifying...
Hello T-SQL experts I have a table containing team codes and descriptions. Unfortunately, many...
Hi, In my Always On Availability environment, I am seeing two encrypt_option values as...
I have this data in a SQL Server 2019 database:
Customer table CustomerID CustomerName 1 Steve 2 Andy 3 Brian 4 Allen 5 Devin 6 Sally OrderHeader table OrderID CustomerID OrderDate 1 1 2024-02-01 2 1 2024-03-01 3 3 2024-04-01 4 4 2024-05-01 6 4 2024-05-01 7 3 2024-06-07 8 2 2024-04-07I want a list of all customers and their order counts for a period of time, including zero orders. If I run this query, how many rows are returned?
SELECT c.CustomerName, COUNT(oh.OrderID) FROM dbo.Customer AS c LEFT JOIN dbo.OrderHeader AS oh ON oh.CustomerID = c.CustomerID WHERE oh.Orderdate > '2024/04/01' GROUP BY c.CustomerNameSee possible answers