Group BY question

  • Hi,

    I have the following data and looikng to get the result of top 2 values of each depart ment and their names.

    NamedeptCount

    aaaccount12

    bbaccount24

    ccaccount22

    ddIT23

    eeIT67

    ffIT665

    ggIT6456

    hhIT5

    iiIT7

    llaccount76

    I want to select top 2 values from each department. How can I do this

    I want the following result.

    gg IT 6456

    ff IT 665

    ll account 76

    bb account 24

    Any help would be appreciated.

    Thanks.

  • Read up in your text book or Books On Line about the Top option and the GROUP BY function. You should be able to make it work from there. You should also look into subqueries.

    If you need further help, post the code you have so far and we can take it from there.

    Toni

  • This will do it... assuming that names are unique...

    --===== Simulate the OPs table

    -- This is NOT part of the solution

    DECLARE @yourtable TABLE

    (Name VARCHAR(10), Dept VARCHAR(10), Count INT)

    INSERT INTO @yourtable

    (Name, Dept, Count)

    SELECT 'aa','account','12' UNION ALL

    SELECT 'bb','account','24' UNION ALL

    SELECT 'cc','account','22' UNION ALL

    SELECT 'dd','IT','23' UNION ALL

    SELECT 'ee','IT','67' UNION ALL

    SELECT 'ff','IT','665' UNION ALL

    SELECT 'gg','IT','6456' UNION ALL

    SELECT 'hh','IT','5' UNION ALL

    SELECT 'ii','IT','7' UNION ALL

    SELECT 'll','account','76'

    --===== Produce the desired output

    SELECT t1.*

    FROM @yourtable t1

    WHERE t1.Name IN

    (

    SELECT TOP 2 --Change this number to vary # output

    t2.Name

    FROM @yourtable t2

    WHERE t2.Dept = t1.Dept

    ORDER BY t2.Count DESC

    )

    ORDER BY t1.Dept,

    t1.Count DESC

    I suspect that you didn't get a "code example answer" the first time because it's a bit of a pain to setup a test with the way you listed your example data. Please read the following for faster/better answers on future posts... thanks...

    http://www.sqlservercentral.com/articles/Best+Practices/61537/

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

    Change is inevitable... Change for the better is not.


    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)

  • Shoot... I hope I didn't just help someone do their homework without them trying themselves, first...

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

    Change is inevitable... Change for the better is not.


    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)

  • What's done is done. As you guessed, I did not post the code directly myself (instead providing areas to review that would allow creation of the solution) as it seemed a general question that would appear in homework.

    Toni

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