April 21, 2005 at 5:25 am
Hi Folks
Is there an easy way to display a value such as 1 342 671 as 1,3?
I constructed a case statement that manipulates the string based on the length, I am sure someone has a more elegant way of doing it?
declare @Value varchar(10)
begin
Select @Value = left(@Value, len(@Value)-6) + ',' + substring(@Value, 3,3)
end
else if len(@Value) = 7
begin
Select @Value = left(@Value, len(@Value)-6) + ',' + substring(@Value, 2,3)
end
else if len(@Value) = 6
begin
Select @Value = '0,' + substring(@Value, 1,3)
end
else if len(@Value) = 5
begin
Select @Value = '0,0' + substring(@Value, 1,3)
end
else if len(@Value) = 4
begin
Select @Value = '0,00' + substring(@Value, 1,3)
end
Select @Value
April 21, 2005 at 5:38 am
ROUND function
select round(1342671.000/1000000,1) ==> 1.3
select round(13426.000/1000000,1) ==> 0.0
etc.
Ville
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