September 9, 2022 at 8:02 am
The program becomes vulnerable to SQL injection if user input is added to a SQL query without change, as in the example below:
$unsafe_variable = $_POST['user_input'];
mysql_query("INSERT INTOtable
(column
) VALUES ('$unsafe_variable')");
That's because the user can input something like value'); DROP TABLE table;--, and the query becomes:
INSERT INTOtable
(column
) VALUES('value'); DROP TABLE table;--')
What steps may be taken to stop this from occurring?
September 9, 2022 at 9:29 am
do not allow for dynamic sql to be used.
Provide the needed stored procedures that accept all input parameters and only grant the application account execute authority for the sprocs.
Johan
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September 9, 2022 at 1:45 pm
The program becomes vulnerable to SQL injection if user input is added to a SQL query without change, as in the example below:
$unsafe_variable = $_POST['user_input'];
mysql_query("INSERT INTO table (column) VALUES ('$unsafe_variable')"); That's because the user can input something like value'); DROP TABLE table;--, and the query becomes:
INSERT INTO table (column) VALUES('value'); DROP TABLE table;--')What steps may be taken to stop this from occurring?
What I normally do is to use sys.dm_exec_describe_first_result_set to evaluate if the query returns a valid result set description and if it doesn't, then discard it.
😎
For multi-statement entries, chop it by the first statement delimiter and always discard the rest!
One other thing to look out for is when statements are passed as hex strings, might need an extra step as naive pattern matching will not catch statement separators!
September 12, 2022 at 10:14 am
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September 12, 2022 at 10:15 am
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September 12, 2022 at 10:21 am
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September 13, 2022 at 10:36 pm
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