Consolidating Two or More Identical Rows into One

• ssandeepksh

  SSC Journeyman

  Points: 91

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  December 5, 2014 at 9:03 am

  #397738

  Hi,

  Can you please help to solve this?

  I have a table with many identical rows which has different numerical value only in once column.

  I want these two or more identical rows to be selected as only one row with the sum of all different numerical values.

  Example:-

  Row1: A B 4 C D

  Row2: A B 5 C D

  Output: A B 9 C D

  Thanks,

  Sandeep

• ChrisM@Work

  SSC Guru

  Points: 186127

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  December 5, 2014 at 9:09 am

  #1763002

  ssandeepksh (12/5/2014)

  ---

  Hi,

  Can you please help to solve this?

  I have a table with many identical rows which has different numerical value only in once column.

  I want these two or more identical rows to be selected as only one row with the sum of all different numerical values.

  Example:-

  Row1: A B 4 C D

  Row2: A B 5 C D

  Output: A B 9 C D

  Thanks,

  Sandeep

  This has to be homework since you would learn about aggregates in your first few weeks or even days of using SQL. So here's a suggestion to help you, as a full answer would teach you nothing at all.

  Try GROUP BY and SUM().

  ^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

  For fast, accurate and documented assistance in answering your questions, please read this article.
  Understanding and using APPLY, (I) and (II) Paul White
  Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

• Chris Hurlbut

  SSCarpal Tunnel

  Points: 4162

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  December 5, 2014 at 2:02 pm

  #1763071

  SELECT column_A,

  column_B,

  SUM(Column_4)

  column_C,

  column_D

  FROM dbo.Test_Table

  GROUP BY column_A,

  column_B,

  column_C,

  column_D

• ssandeepksh

  SSC Journeyman

  Points: 91

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  December 8, 2014 at 4:18 am

  #1763231

  I have been moron last week and asked such a silly question. Thanks for your help 🙂