To detect dead lock exists?

  • Hello Friends,

    I am facing a challenge to develop an algorithm in T-SQL.

    Algorithm Logic:

    A depends of B and B depends of A, or indirectly, for example A depends of B, B depends of C and C depends of A. In this case, it will create a dead lock. My aim is to identify this and insert them in a table.

    For example: The data is shown in the table like this.

    Source_idDependingSources

    187 188

    188 189

    189 187

    In this case -- A(187) is dependent on B(188), B(188) is dependent C(189), C(189) is dependent on A(187). This create a dead lock here.

    So I have to insert a line like this "The dependent sources are 187,188,189". So how to detect the dependencies like this with T-SQL code.

    I need the code / ideas / concepts or help in implementing this.

    Please help. Thanks in advance.

  • Cannot see where exactly you're expecting a dead-lock.

    May be if you follow: http://www.sqlservercentral.com/articles/Best+Practices/61537/

    we may be more helpfull...

    _____________________________________________
    "The only true wisdom is in knowing you know nothing"
    "O skol'ko nam otkrytiy chudnyh prevnosit microsofta duh!":-D
    (So many miracle inventions provided by MS to us...)

    How to post your question to get the best and quick help[/url]

  • shyamhr (3/8/2012)


    In this case -- A(187) is dependent on B(188), B(188) is dependent C(189), C(189) is dependent on A(187). This create a dead lock here.

    That's not a deadlock, that's a dependency loop (deadlock is a circular chain of locks)

    Gail Shaw
    Microsoft Certified Master: SQL Server, MVP, M.Sc (Comp Sci)
    SQL In The Wild: Discussions on DB performance with occasional diversions into recoverability

    We walk in the dark places no others will enter
    We stand on the bridge and no one may pass
  • MS SQL Server already have a mechanism to find dead locks.

    What's you goal?

    Its a home work?

  • Yes, this is a kind of challenge in T-SQL coding assigned to me.

  • That is true Gila. How can I achieve find these combinations that there is a loop in place. Thanks.

  • I would probably use a recursive CTE with checks to see it I ever get dependant = starting value.

    Give it a try (Books Online has some good resources on recursive CTEs), if you get stuck post your code and we'll help further. Since it's an exercise I'm not doing it for you.

    Gail Shaw
    Microsoft Certified Master: SQL Server, MVP, M.Sc (Comp Sci)
    SQL In The Wild: Discussions on DB performance with occasional diversions into recoverability

    We walk in the dark places no others will enter
    We stand on the bridge and no one may pass
  • Solution withdrawn as per Gail's note:

    Give it a try (Books Online has some good resources on recursive CTEs), if you get stuck post your code and we'll help further. Since it's an exercise I'm not doing it for you.

    Just one more thing: Depends on exact requirements, if you have predefined maximum possible number of items in the dependency loop (let say in your case it is 3), you may not need to use recursive CTE, JOINS will do just fine.

    _____________________________________________
    "The only true wisdom is in knowing you know nothing"
    "O skol'ko nam otkrytiy chudnyh prevnosit microsofta duh!":-D
    (So many miracle inventions provided by MS to us...)

    How to post your question to get the best and quick help[/url]

  • Thanks Gila and SSC. I will keep you posted.

  • Looks like OP managed to see my withdrawn solution, I wasn't quick enough to hit a button... :hehe:

    _____________________________________________
    "The only true wisdom is in knowing you know nothing"
    "O skol'ko nam otkrytiy chudnyh prevnosit microsofta duh!":-D
    (So many miracle inventions provided by MS to us...)

    How to post your question to get the best and quick help[/url]

  • Hello Friends,

    My task is almost over. But I am struck @ final step. I was able to get the desired output with a Recursive CTE function.

    But the challenge now here is :

    Sample data

    Dependency List

    47,48,49,92,93,94,95,96,108,107

    47,48,49,92,93,94,95,96,107,108

    27,37

    37,27

    If you see there are two rows for the same combination of numbers. How can I order them to get only one row for a single combination. This is the last step.

    Note: This is a varchar column.

    This is the last step. If I am done with this the SP will be ready in couple of hours. So Please help me.......

  • Post the code you have so far. Just want to see how you've done it.

    Gail Shaw
    Microsoft Certified Master: SQL Server, MVP, M.Sc (Comp Sci)
    SQL In The Wild: Discussions on DB performance with occasional diversions into recoverability

    We walk in the dark places no others will enter
    We stand on the bridge and no one may pass
  • Sure... Here you go ....

    ;with tmp(Source_ID, DependsOn, DependingSources) as

    ( select CAST(Source_ID AS INT),

    CAST(LEFT(DependingSources, CHARINDEX(',',DependingSources+',')-1) AS NVARCHAR(50)),

    CAST(STUFF(DependingSources, 1, CHARINDEX(',',DependingSources+','), '')AS NVARCHAR(50))

    from TEC.moris_source_id_India WHERE Active=1 AND DependingSources<>''

    union all

    select CAST(Source_ID AS INT),

    CAST(LEFT(DependingSources, CHARINDEX(',',DependingSources+',')-1)AS NVARCHAR(50)),

    CAST(STUFF(DependingSources, 1, CHARINDEX(',',DependingSources+','), '') AS NVARCHAR(50))

    from tmp where DependingSources > '' )

    select Source_ID, DependsOn INTO #Temp from tmp order by Source_ID

    SELECT * FROM #Temp

    GO

    --

    ;WITH Final_CTE AS (

    SELECT Source_ID, DependsWithCommas= CAST(DependsOn AS NVARCHAR(100)) ,LEN(DependsOn) As DepLen

    FROM #Temp

    --WHERE ManagerID IS NULL

    UNION ALL

    SELECT T.Source_ID, CAST(DependsWithCommas +','+T.DependsOn AS NVARCHAR(100)),LEN(DependsWithCommas) AS DepLen

    FROM #Temp T

    INNER JOIN Final_CTE Fcte ON Fcte.Source_ID = T.DependsOn

    WHERE DependsWithCommas NOT LIKE '%'+CAST(T.DependsOn AS NVARCHAR(100))+'%'--LEN(DependsWithCommas)<50

    )

    SELECT * INTO #TempNew

    FROM Final_CTE

    SELECT * FROM #TempNew

    SELECT TT.* INTO #TempFinal FROM

    (SELECT TN.Source_ID,TN.DependsWithCommas,TN.DepLen FROM #TempNew TN

    WHERE LTRIM(RTRIM(TN.DependsWithCommas)) LIKE '%'+CAST(TN.Source_ID AS NVARCHAR(100))+'%') TT

    --AND DepLen = (SELECT MAX(TN.DepLen) FROM #TempNew TN GROUP BY TN.Source_ID )

    INNER JOIN

    (SELECT Source_ID, MAX(DepLen) AS MaxLen FROM #TempNew GROUP BY Source_ID) GM

    ON GM.Source_ID = TT.Source_ID AND GM.MaxLen=TT.DepLen

    SELECT * FROM #TempFinal

    SELECT Distinct DependsWithCommas from #TempFinal

    --DROP TABLE #Temp

    --DROP TABLE #TempNew

    -- DROP TABLE #TempFinal

  • There are lots better ways to concatenate with commas than you have there. Look around for the XML Path method. When you find that, consider keeping 2 copies of the concatenated string, one in the dependency order and one just in numeric order. The second will allow you to identify duplicates (probably with Row_Number)

    Gail Shaw
    Microsoft Certified Master: SQL Server, MVP, M.Sc (Comp Sci)
    SQL In The Wild: Discussions on DB performance with occasional diversions into recoverability

    We walk in the dark places no others will enter
    We stand on the bridge and no one may pass

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