Don't know the answer, can't form the question...and, besides, I'm a chicken (wearing a hat)

Question

Post reply

Don't know the answer, can't form the question...and, besides, I'm a chicken (wearing a hat)

mark-o-751804

Valued Member

Points: 50
More actions
May 30, 2008 at 6:28 pm

#380834

Hi. Sorry in advance for the rather long post.
The database administrator who worked for me left and I am filling in the best I can.
I'd love to learn how to do all the magic you all do on the programming side, but (hat's off to you), but I am both pressed for time and a chicken (even if I don't have a hat any more).
So...after you've fished the cheese (to go with my whine)...
I'd very much appreciate any recommendations for a good, FREE SQL site (did I mention that I'm cheap) for "advanced" querying that stops short of scripts, stored procedures and other programming that I can look at until I can get up to speed ? I've tried a few, but not much luck.
Thank you all

Viewing 15 posts - 1 through 15 (of 19 total)

You must be logged in to reply to this topic. Login to reply

Jeff Moden SSC Guru Points: 1004340 More actions · Answer 1

Which sites did you try that you were disappointed with?

--Jeff Moden

RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

Change is inevitable... Change for the better is not.

Helpful Links:
How to post code problems
How to Post Performance Problems
Create a Tally Function (fnTally)

Peter Vramby Default port Points: 1439 More actions · Answer 2

Last time I was looking for a specific topic, I came across this nice site.

The site is called "SQL Server 2000 Survival Guide".

http://www.akadia.com/services/sqlsrv_programming.html

Most of the topics are still the same in SQL 2005.

Enjoy your reading,

Peter

pduplessis-723389 SSChampion Points: 10599 More actions · Answer 3

http://www.sqlservercentral.com/Forums is most probably the best site that I have ever encountered which offers darn good advice.

Just shoot with your question, and you will have a relatively good answer in a reasonable amount of time.

Good luck, and welcome on board

~PD

ps> Before posting anything, please access Jeff's link on some good forum manners

Christopher Stobbs SSC-Insane Points: 21098 More actions · Answer 4

HI there,

I agree, SSC is one of the best sites for advice and learning that I have come across 🙂

Don't be scared fail be excited to learn 😉

thanks

Chris

----------------------------------------------
Try to learn something about everything and everything about something. - Thomas Henry Huxley

:w00t:
Posting Best Practices[/url]
Numbers / Tally Tables[/url]

SQL-4-Life

GSquared SSC Guru Points: 260824 More actions · Answer 5

As others have said, this is a great site for asking questions and getting articles.

- Gus "GSquared", RSVP, OODA, MAP, NMVP, FAQ, SAT, SQL, DNA, RNA, UOI, IOU, AM, PM, AD, BC, BCE, USA, UN, CF, ROFL, LOL, ETC
Property of The Thread

"Nobody knows the age of the human race, but everyone agrees it's old enough to know better." - Anon

Steve Jones - SSC Editor SSC Guru Points: 736212 More actions · Answer 6

Keep posting here, and we'll try to help.

Honestly, I'd recommend you beg for some $$ to pick up one SQL 2005 book, any of the admin books (check half.com) and read through it. It will help guide you and we'll be happy to help you understand.

mark-o-751804 Valued Member Points: 50 More actions · Answer 7

Is there a way to take a set of records from one table in a database and compare them to a set of records in a second table and return the results without hardwiring the desired results set into my query?

For example

Table 1 - Guys

GUYCHAR

MarkTall

MarkDark

MarkHandsome

JoeTall

JoeBlond

JoeHandsome

Table 2 –Women

WOMANDESIRED

JudyTall

JudyDark

JudyHandsome

AmyTall

AmyHandsome

Despite the obvious shallowness of my query, I want the results to be:

WOMANGUY

JudyMark

AmyMark

AmyJoe

pduplessis-723389 SSChampion Points: 10599 More actions · Answer 8

Hey,

Yes you can, but it will return slightly more than what you are bargaining on

select

W.WOMAN, G.GUY

from Guys as G

inner join Women as W

on G.Desired = W.Desired

This will return any matches based on the desired field

WOMAN GUY Fields that would match

Judy Mark (Tall/Dark/Handsome)

Judy Joe (Tall/Handsome)

Amy Mark (Tall/Handsome)

Amy Joe (Tall/Handsome)

Hope this makes sense

~PD

ps> I agree with Steve, maybe forking out a few pennies on a beginners TSQL manual will assist you in the longer term, there normally is some great examples that you could follow

RBarryYoung SSC Guru Points: 143329 More actions · Answer 9

I think that this will do it:

[font="Courier New"]SELECT DISTINCT

w.WOMAN,

g.GUY

FROM Guys g

INNER JOIN Women w ON (w.DESIRED = g.CHAR) --has at least one match

--Need more conditions since the above is too loose

-- so make sure that all of this woman's desires

-- are matched by this guy, or exclude him

WHERE NOT EXISTS( SELECT *

FROM Women w2

WHERE w2.WOMAN = w.WOMAN --same woman as the outer query

AND NOT EXISTS( SELECT *

FROM Guys g2

WHERE g2.GUY = g.GUY --and same guy as outer query

AND w2.DESIRED = g2.CHAR --but some desire is not matched

)

[/font]

[font="Times New Roman"]-- RBarryYoung[/font], [font="Times New Roman"] (302)375-0451[/font] blog: MovingSQL.com, Twitter: @RBarryYoung [font="Arial Black"]
Proactive Performance Solutions, Inc. [/font][font="Verdana"] "Performance is our middle name."[/font]

mark-o-751804 Valued Member Points: 50 More actions · Answer 10

OK, thanks, makes sense...now suppose I throw in another curveball

Table 1 - Guys

GUY CHAR

Mark Tall

Mark Dark

Mark Handsome

Mark Rich

Joe Tall

Joe Blond

Joe Handsome

Table 2 –Women

WOMAN DESIRED

Judy Tall

Judy Dark

Judy Handsome

Amy Tall

Amy Handsome

i.e. my list of characteristics on the "GUYs" side includes items that the WOMAN doesn't care about (Judy want a man who is tall darak and handsome, but doesn't care if he is rich or not)? Won't the above query exclude him?

matt.mallen SSC Veteran Points: 294 More actions · Answer 11

This might work for you

SELECT DISTINCT WM.Woman, GY.Guy

FROM Woman WM

INNER JOIN Guy GY ON GY.Char=WM.Desired

WHERE (SELECT COUNT(1)

FROM Woman WMM

WHERE WMM.Woman=WM.Woman)

=

(SELECT COUNT(1)

FROM Woman WMM

INNER JOIN Guy GYY ON GYY.Char=WMM.Desired

WHERE WMM.Woman=WM.Woman AND GYY.Guy=GY.Guy)

*edit* this may not work if you have any duplicate rows

RBarryYoung SSC Guru Points: 143329 More actions · Answer 12

mark-o (6/2/2008)
i.e. my list of characteristics on the "GUYs" side includes items that the WOMAN doesn't care about (Judy want a man who is tall darak and handsome, but doesn't care if he is rich or not)? Won't the above query exclude him?

My query already assumes that. It only excludes men who do not match every desire of a woman. Extra CHARs have no effect.

[font="Times New Roman"]-- RBarryYoung[/font], [font="Times New Roman"] (302)375-0451[/font] blog: MovingSQL.com, Twitter: @RBarryYoung [font="Arial Black"]
Proactive Performance Solutions, Inc. [/font][font="Verdana"] "Performance is our middle name."[/font]

Matt Miller (4) SSC Guru Points: 124210 More actions · Answer 13

rbarryyoung (6/2/2008)
My query already assumes that. It only excludes men who do not match every desire of a woman. Extra CHARs have no effect.

Save yourself some time....we ALL know that the answer to that query will ALWAYS be Null.....:P

----------------------------------------------------------------------------------
Your lack of planning does not constitute an emergency on my part...unless you're my manager...or a director and above...or a really loud-spoken end-user..All right - what was my emergency again?

mark-o-751804 Valued Member Points: 50 More actions · Answer 14

mark-o-751804

Valued Member

Points: 50

June 2, 2008 at 1:57 pm

#823279

Yes, I did set myself up for it...