SQL Query with CTE or other...!

  • question

    Any one can help me please with this issue? I really appreciate this help. The number of Answer is dynamic.

    • This topic was modified 5 years, 1 month ago by  carloscris.
    • This topic was modified 5 years, 1 month ago by  carloscris.
  • You could use a dynamic cross-tab query.  Take a look at the following 2 articles by Jeff Moden

    Cross Tabs and Pivots, Part 1 – Converting Rows to Columns

    Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs

     

  • You can achieve this using the below query:

    SELECT ID, Question, [A], , [C], [OPTION]

    FROM

    (

    SELECT A.ID,Answer,Question

    FROM Answer A

    inner join Question Q on A.ID = Q.QuestionID

    ) As PivotTable

    PIVOT

    (

    MAX(Answer)

    FOR Answer IN ([A], , [C], [OPTION])

    ) AS P

  • Hi Sumathi,

    I use this query all ready and work. But the problem is because we never know how many column can be...idea is create it automatically. And other issue is concatenate all in just one single column like: Q1 >>> |A, B, C| in same column.

    Many thanks

  • Maybe this will give you what you want:

    --** Data set up ***************************************************************
    CREATE TABLE dbo.questions (
    question_id int PRIMARY KEY,
    question varchar(1000) NOT NULL
    )
    INSERT INTO dbo.questions VALUES
    (1, 'Q1'), (2, 'Q2'),
    (3, 'Q3'), (4, 'Q4')

    CREATE TABLE dbo.answers (
    question_id int NOT NULL,
    answer_sequence smallint NOT NULL,
    answer varchar(1000) NOT NULL
    )
    TRUNCATE TABLE dbo.answers
    INSERT INTO dbo.answers VALUES
    (1, 10, 'A'), (1, 20, 'B'), (1, 30, 'C'), (1, 40, 'OPTION'),
    (2, 10, 'A'), (2, 20, 'B'), (2, 30, 'C'),
    (3, 10, 'E'), (3, 20, 'F')

    --** Actual code ***************************************************************
    DECLARE @max_number_of_answers smallint
    DECLARE @sql varchar(max)

    SELECT @max_number_of_answers = (
    SELECT TOP (1) COUNT(*)
    FROM answers
    GROUP BY question_id
    ORDER BY COUNT(*) DESC )
    --PRINT @max_number_of_answers
    ;WITH
    cte_tally10 AS (
    SELECT * FROM (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) AS numbers(number)
    ),
    cte_tally1000 AS (
    SELECT ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) AS number
    FROM cte_tally10 c1
    CROSS JOIN cte_tally10 c2 CROSS JOIN cte_tally10 c3
    )
    SELECT @sql = STUFF(CAST((
    SELECT REPLACE(', MAX(CASE WHEN answer_number = ? THEN answer ELSE '''' END)' +
    ' AS answer?', '?', CAST(t.number AS varchar(5)))
    FROM cte_tally1000 t
    WHERE t.number <= @max_number_of_answers
    ORDER BY t.number
    FOR XML PATH(''), TYPE
    ) AS varchar(max)), 1, 2, '')
    --PRINT @sql
    SET @sql = 'SELECT a.question_id, ' + @sql + ' FROM ( ' +
    'SELECT *, ROW_NUMBER() OVER(PARTITION BY question_id
    ORDER BY answer_sequence) AS answer_number ' +
    'FROM dbo.answers ) AS a ' +
    'INNER JOIN dbo.questions q ON q.question_id = a.question_id ' +
    'GROUP BY a.question_id ' +
    'ORDER BY question_id '
    --PRINT @sql
    EXEC(@sql)

    INSERT INTO dbo.answers VALUES(2, 40, 'D'),(2, 50, 'E'), (2, 60, 'F'), (2, 70, 'G')
    SELECT 'Added 4 answers for Q#2!'
    SELECT @max_number_of_answers = (
    SELECT TOP (1) COUNT(*)
    FROM answers
    GROUP BY question_id
    ORDER BY COUNT(*) DESC )
    ;WITH
    cte_tally10 AS (
    SELECT * FROM (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) AS numbers(number)
    ),
    cte_tally1000 AS (
    SELECT ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) AS number
    FROM cte_tally10 c1
    CROSS JOIN cte_tally10 c2 CROSS JOIN cte_tally10 c3
    )
    SELECT @sql = STUFF(CAST((
    SELECT REPLACE(', MAX(CASE WHEN answer_number = ? THEN answer ELSE '''' END)' +
    ' AS answer?', '?', CAST(t.number AS varchar(5)))
    FROM cte_tally1000 t
    WHERE t.number <= @max_number_of_answers
    ORDER BY t.number
    FOR XML PATH(''), TYPE
    ) AS varchar(max)), 1, 2, '')
    --PRINT @sql
    SET @sql = 'SELECT a.question_id, ' + @sql + ' FROM ( ' +
    'SELECT *, ROW_NUMBER() OVER(PARTITION BY question_id
    ORDER BY answer_sequence) AS answer_number ' +
    'FROM dbo.answers ) AS a ' +
    'INNER JOIN dbo.questions q ON q.question_id = a.question_id ' +
    'GROUP BY a.question_id ' +
    'ORDER BY question_id '
    --PRINT @sql
    EXEC(@sql)

    SQL DBA,SQL Server MVP(07, 08, 09) "It's a dog-eat-dog world, and I'm wearing Milk-Bone underwear." "Norm", on "Cheers". Also from "Cheers", from "Carla": "You need to know 3 things about Tortelli men: Tortelli men draw women like flies; Tortelli men treat women like flies; Tortelli men's brains are in their flies".

  • Can the pivoting be done in Excel or whatever reporting tool your company uses?  While I have seen the dynamic SQL type solutions work for this, it's probably best to do this type of pivot outside of the database.

  • No Chris,

    I have to be done in SQL Server query.

    Thanks

  • It is easy enough, if you want one column for your answer:

    DECLARE @Questions TABLE ([ID] int, [Question] VARCHAR(64))
    INSERT INTO @Questions VALUES(1,'Q1'),(2,'Q2'),(3,'Q3'),(4,'Q4');

    DECLARE @Answers TABLE ([ID] int, [Answer] VARCHAR(64))
    INSERT INTO @Answers VALUES(1,'A'),(1,'B'),(1,'C'),(1,'OPTION'),(2,'A'),(2,'B'),(2,'C'),(3,'E'),(3,'F');

    SELECT
    q.[Question]
    ,STUFF((
    SELECT CONCAT(',',a.[Answer]) FROM @Answers a
    WHERE q.[ID] = a.[ID]
    FOR XML PATH('')
    ),1,1,'') AS [Answers]
    FROM
    @Questions q

    This should work on SQL2012+.

    If you were using SQL 2017, you could use STRING_AGG() rather than the STUFF/FOR XML trick

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