Efficient way to determine if a criteria is met

• Sridhar-137443

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  February 19, 2015 at 8:17 am

  #315488

  Hi, I am trying to find out an efficient way to determine if employee meets a criteria. We have employee table that has following information

  Company, Empno, Level1, Level2, Level3, Level4, Level5

  we have criteria table as follows

  GridId Type TypeValue NextGridId

  0001 Level1 ABC 0002

  0002 Level2 123 0003

  0003 Level3 A12 0004

  So, I wrote a scalar value function to loop through each record and if employee has TypeValue in the employee table for all the records in the criteria table, the employee meets the criteria.

  But if I want to do this for say 100 employees, it is not efficient to call the function for each employee. Any ideas on how to make it efficient?

  Thanks,

  Sridhar.

• Phil Parkin

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  February 19, 2015 at 8:22 am

  #1778655

  Sridhar-137443 (2/19/2015)

  ---

  Hi, I am trying to find out an efficient way to determine if employee meets a criteria. We have employee table that has following information

  Company, Empno, Level1, Level2, Level3, Level4, Level5

  we have criteria table as follows

  GridId Type TypeValue NextGridId

  0001 Level1 ABC 0002

  0002 Level2 123 0003

  0003 Level3 A12 0004

  So, I wrote a scalar value function to loop through each record and if employee has TypeValue in the employee table for all the records in the criteria table, the employee meets the criteria.

  But if I want to do this for say 100 employees, it is not efficient to call the function for each employee. Any ideas on how to make it efficient?

  Thanks,

  Sridhar.

  I think we need more info here.

  The link between your two tables is unclear.

  Please post DDL, sample data and desired results as per the link in my signature.

  The absence of evidence is not evidence of absence
  - Martin Rees
  The absence of consumable DDL, sample data and desired results is, however, evidence of the absence of my response
  - Phil Parkin

• A. Harmon

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  February 23, 2015 at 1:34 pm

  #1779404

  A Table-Valued function would be much more efficient than a scalar function. I agree we need a bit more information on how your tables are related.

• Dwain Camps

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  February 23, 2015 at 5:28 pm

  #1779452

  I would add to this that we'll probably need to know what values are stored in the Leveln columns of the employee table.

  DDL and consumable sample data (INSERTs) would probably get you a tested solution rapidly.

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