Are you asking for something like this?
SELECT fg.name AS filegroup, df.name AS filename, df.physical_name
FROM sys.filegroups fg
JOIN sys.database_files df ON fg.data_space_id = df.data_space_id
If not, I feel like there's a language barrier.
Luis C.
General Disclaimer:
Are you seriously taking the advice and code from someone from the internet without testing it? Do you at least understand it? Or can it easily kill your server?
How to post data/code on a forum to get the best help: Option 1 / Option 2