January 8, 2014 at 11:48 pm
Dear Friends
i ve the scenario like
The list of customer's was billed on 01-apr-2011
custname products value bill_date bill_no
ram Milk 25 01-apr-2011 25
ram Perfume 225 01-apr-2011 25
sam Egg 50 01-apr-2011 26
sam Medicine 125 01-apr-2011 26
now i wanna to extract the maximum billed value from above and display on my result like
custName products Max_sales billed billno
ram Perfume 225 01-apr-2011 25
sam Medicine 125 01-apr-2011 26
how to write code for these scenario?
do the need full
thanks
rocky
January 9, 2014 at 1:20 am
How about a couple of things -- code we can read, and some sample data? (CREATE TABLE script(s) and INSERTs). And while I'm being demanding, how about an example of the expected output?
January 9, 2014 at 2:02 am
Hey Sri ,
Lets Consider table like
create table Bill_max
(
bill_no int,
cust_det int,
product varchar(20),
Price int,
bill_date datetime
)
insert into bill_max(bill_no, cust_det,product,prize,Bill_date) values('25','ram','Milk','25','01-apr-2013')
insert into bill_max(bill_no, cust_det,product,prize,Bill_date) values('25','ram','Perfume','150','01-apr-2013')
insert into bill_max(bill_no, cust_det,product,prize,Bill_date) values('26','sam','Fruits','50','01-apr-2013')
insert into bill_max(bill_no, cust_det,product,prize,Bill_date) values('26','sam','Books','500','01-apr-2013')
select * from bill_max
above details ll show here
now i wanna to display max sales for billed cust.(i.e)
bill_no Cust_det product Max_prize bill_date
25 ram perfume 150 01-apr-2013
26 sam Book 500 01-apr-2013
My expectation when the customer is billed many item on same bill_no but i wanna separate only highest value in that (i.e with out rank)
how to do that?
January 9, 2014 at 6:18 am
So how about.....
SELECT
bm.bill_no,
bm.cust_det,
bm.product,
bm.price,
bm.bill_date
FROM bill_max bm
INNER JOIN
(
SELECT MAX(price) [max_price], cust_det
FROM bill_max
GROUP BY cust_det
) AS max_price
ON max_price.max_price = bm.price
AND max_price.cust_det = bm.cust_det
January 9, 2014 at 6:43 am
raghuldrag (1/9/2014)
Hey Sri ,Lets Consider table like
create table Bill_max
(
bill_no int,
cust_det int,
product varchar(20),
Price int,
bill_date datetime
)
insert into bill_max(bill_no, cust_det,product,prize,Bill_date) values('25','ram','Milk','25','01-apr-2013')
insert into bill_max(bill_no, cust_det,product,prize,Bill_date) values('25','ram','Perfume','150','01-apr-2013')
insert into bill_max(bill_no, cust_det,product,prize,Bill_date) values('26','sam','Fruits','50','01-apr-2013')
insert into bill_max(bill_no, cust_det,product,prize,Bill_date) values('26','sam','Books','500','01-apr-2013')
select * from bill_max
above details ll show here
now i wanna to display max sales for billed cust.(i.e)
bill_no Cust_det product Max_prize bill_date
25 ram perfume 150 01-apr-2013
26 sam Book 500 01-apr-2013
My expectation when the customer is billed many item on same bill_no but i wanna separate only highest value in that (i.e with out rank)
how to do that?
(i.e with out rank)
Why is that? I wouldn't use RANK() for this anyway, I'd use ROW_NUMBER().
For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden
January 9, 2014 at 6:56 am
;WITH a (bill_no,cust_det,product,Price,bill_date,rowid)
AS (SELECT bill_no,cust_det,product,Price,bill_date,ROW_NUMBER() OVER (PARTITION BY bill_no ORDER BY price DESC) FROM Bill_max)
SELECT bill_no,cust_det,product,Price,bill_date
FROM a
WHERE rowid = 1
ORDER BY bill_no ASC
Far away is close at hand in the images of elsewhere.
Anon.
January 9, 2014 at 6:59 am
David Burrows (1/9/2014)
;WITH a (bill_no,cust_det,product,Price,bill_date,rowid)
AS (SELECT bill_no,cust_det,product,Price,bill_date,ROW_NUMBER() OVER (PARTITION BY bill_no ORDER BY price DESC) FROM Bill_max)
SELECT bill_no,cust_det,product,Price,bill_date
FROM a
WHERE rowid = 1
ORDER BY bill_no ASC
Exactly! :hehe:
For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden
Viewing 7 posts - 1 through 6 (of 6 total)
You must be logged in to reply to this topic. Login to reply