increment id based on column value

  • Hi !

    I hope that you can show me how to do it avoiding using loop. I need to group records imported from flat file by ID. Column LegacyID is identity column. I need new ID incremented on next value='H'. Thank you.Mark Gorelik

    create table LoadTest (legacyid int not null ,field1 varchar(5) not null, newid int null)

    insert into LoadTest (legacyid ,field1)

    SELECT 2,'H'

    UNION ALL

    SELECT 3,'C'

    UNION ALL

    SELECT 4,'S'

    UNION ALL

    SELECT 5,'O'

    UNION ALL

    SELECT 6,'I'

    UNION ALL

    SELECT 7,'I'

    UNION ALL

    SELECT 8,'I'

    UNION ALL

    SELECT 9,'H'

    UNION ALL

    SELECT 10,'C'

    UNION ALL

    SELECT 11,'S'

    UNION ALL

    SELECT 12,'O'

    UNION ALL

    SELECT 13,'I'

    UNION ALL

    SELECT 14,'I'

    UNION ALL

    SELECT 15,'I'

    UNION ALL

    SELECT 16,'I'

    UNION ALL

    SELECT 17,'I'

    UNION ALL

    SELECT 18,'I'

    UNION ALL

    SELECT 19,'N'

    UNION ALL

    SELECT 20,'H'

    UNION ALL

    SELECT 21,'C'

    UNION ALL

    SELECT 22,'S'

    UNION ALL

    SELECT 23,'O'

    UNION ALL

    SELECT 24,'I'

    UNION ALL

    SELECT 25,'I'

    SELECT * FROM LoadTest

    legacyidfield1newid

    ======================================

    2H1

    3C1

    4S1

    5O1

    6I1

    7I1

    8I1

    9H2

    10C2

    11S2

    12O2

    13I2

    14I2

    15I2

    16I2

    17I2

    18I2

    19N2

    20H3

    21C3

    22S3

    23O3

    24I3

    25I3

  • An easy and effective way to do this is by using the quirky update. You must fully understand what it is doing, follow all the rules and test for effectiveness and correct data.

    This article explains it completely http://www.sqlservercentral.com/articles/T-SQL/68467/

    And here's a sample code based on your data.

    CREATE CLUSTERED INDEX IX_LoadTest_LegacyID ON LoadTest( LegacyID)

    DECLARE @New_ID int = 0, @anchor int

    UPDATE LoadTest WITH( TABLOCKX) SET

    @anchor = LegacyID,

    @New_ID = NEWID = @New_ID + CASE WHEN field1 = 'H' THEN 1 ELSE 0 END

    OPTION( MAXDOP 1)

    SELECT *

    FROM LoadTest

    Luis C.
    General Disclaimer:
    Are you seriously taking the advice and code from someone from the internet without testing it? Do you at least understand it? Or can it easily kill your server?

    How to post data/code on a forum to get the best help: Option 1 / Option 2
  • Thank you Luis !

    I tested your solution on real data and for some reason it does not work . ID incremented for field1 value='H' .The rest script updated with one value=209 except field1 ='C' . Value "C" updated with zero. I should say that script worked on submitted test data.Please see attached result.

  • Mark Gorelik (8/14/2013)


    Thank you Luis !

    I tested your solution on real data and for some reason it does not work . ID incremented for field1 value='H' .The rest script updated with one value=209 except field1 ='C' . Value "C" updated with zero. I should say that script worked on submitted test data.Please see attached result.

    My guess is that in your real table you don't have a clustered index on legacyID. The rules for the quirky update are very specific and it will not work correctly unless you follow ALL of them.

    _______________________________________________________________

    Need help? Help us help you.

    Read the article at http://www.sqlservercentral.com/articles/Best+Practices/61537/ for best practices on asking questions.

    Need to split a string? Try Jeff Modens splitter http://www.sqlservercentral.com/articles/Tally+Table/72993/.

    Cross Tabs and Pivots, Part 1 – Converting Rows to Columns - http://www.sqlservercentral.com/articles/T-SQL/63681/
    Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs - http://www.sqlservercentral.com/articles/Crosstab/65048/
    Understanding and Using APPLY (Part 1) - http://www.sqlservercentral.com/articles/APPLY/69953/
    Understanding and Using APPLY (Part 2) - http://www.sqlservercentral.com/articles/APPLY/69954/

  • It does the same with cluster index . must be something else.

  • Could you post the actual table definition (table and column names changed if necessary) with the clustered index and the code you're using?

    Luis C.
    General Disclaimer:
    Are you seriously taking the advice and code from someone from the internet without testing it? Do you at least understand it? Or can it easily kill your server?

    How to post data/code on a forum to get the best help: Option 1 / Option 2
  • Sean Lange (8/14/2013)


    Mark Gorelik (8/14/2013)


    Thank you Luis !

    I tested your solution on real data and for some reason it does not work . ID incremented for field1 value='H' .The rest script updated with one value=209 except field1 ='C' . Value "C" updated with zero. I should say that script worked on submitted test data.Please see attached result.

    My guess is that in your real table you don't have a clustered index on legacyID. The rules for the quirky update are very specific and it will not work correctly unless you follow ALL of them.

    Then can you post your actual DDL for the table and the entire code you executed?

    --Edit--

    Luis beat me to it. πŸ˜›

    _______________________________________________________________

    Need help? Help us help you.

    Read the article at http://www.sqlservercentral.com/articles/Best+Practices/61537/ for best practices on asking questions.

    Need to split a string? Try Jeff Modens splitter http://www.sqlservercentral.com/articles/Tally+Table/72993/.

    Cross Tabs and Pivots, Part 1 – Converting Rows to Columns - http://www.sqlservercentral.com/articles/T-SQL/63681/
    Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs - http://www.sqlservercentral.com/articles/Crosstab/65048/
    Understanding and Using APPLY (Part 1) - http://www.sqlservercentral.com/articles/APPLY/69953/
    Understanding and Using APPLY (Part 2) - http://www.sqlservercentral.com/articles/APPLY/69954/

  • ****** Object: Table [dbo].[tdsMSMCA_Askk] Script Date: 08/14/2013 17:45:48 ******/

    SET ANSI_NULLS ON

    GO

    SET QUOTED_IDENTIFIER ON

    GO

    SET ANSI_PADDING ON

    GO

    CREATE TABLE [dbo].[tdsMSMCA_Askk](

    [ID] [int] IDENTITY(1,1) NOT NULL,

    [Field1] [varchar](255) NULL,

    [Field2] [varchar](255) NULL,

    [Field3] [varchar](255) NULL,

    [Field4] [varchar](255) NULL,

    [Field5] [varchar](255) NULL,

    [Field6] [varchar](255) NULL,

    [Field7] [varchar](255) NULL,

    [Field8] [varchar](255) NULL,

    [Field9] [varchar](255) NULL,

    [Field10] [varchar](255) NULL,

    [Field11] [varchar](255) NULL,

    [Field12] [varchar](255) NULL,

    [Field13] [varchar](255) NULL,

    [Field14] [varchar](255) NULL,

    [Field15] [varchar](255) NULL,

    [Field16] [varchar](255) NULL,

    [Field17] [varchar](255) NULL,

    [Field18] [varchar](255) NULL,

    [Field19] [varchar](255) NULL,

    [Field20] [varchar](255) NULL,

    [Field21] [varchar](255) NULL,

    [Field22] [varchar](255) NULL,

    [Field23] [varchar](255) NULL,

    [Field24] [varchar](255) NULL,

    [DelFlag] [smallint] NULL,

    [NewID] [int] NULL

    ) ON [PRIMARY]

    GO

    SET ANSI_PADDING OFF

    GO

    /****** Object: Index [IX_LoadTest_LegacyID] Script Date: 08/14/2013 17:45:49 ******/

    CREATE CLUSTERED INDEX [IX_LoadTest_LegacyID] ON [dbo].[tdsMSMCA_Askk]

    (

    [ID] ASC

    )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, SORT_IN_TEMPDB = OFF, IGNORE_DUP_KEY = OFF, DROP_EXISTING = OFF, ONLINE = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]

    GO

    /****** Object: Index [ind_tdsMSMCA_askk_0] Script Date: 08/14/2013 17:45:49 ******/

    CREATE NONCLUSTERED INDEX [ind_tdsMSMCA_askk_0] ON [dbo].[tdsMSMCA_Askk]

    (

    [Field1] ASC,

    [ID] ASC

    )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, SORT_IN_TEMPDB = OFF, IGNORE_DUP_KEY = OFF, DROP_EXISTING = OFF, ONLINE = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]

    GO

    DECLARE @New_ID int = 0, @anchor int

    UPDATE dbo.tdsMSMCA_Askk WITH( TABLOCKX)

    SET @anchor = ID,

    @New_ID = NEWID = @New_ID + CASE WHEN field1 = 'H' THEN 1 ELSE 0 END

    OPTION( MAXDOP 1)

    ==================================

    ---Loop that works

    DECLARE

    @wt_row_id INT

    ,@last_@wt_row_id INT

    , @cookie_id varchar(5)

    , @session_id INT

    SELECT @session_id = 1,@last_@wt_row_id=0

    DECLARE cur CURSOR FOR

    SELECT

    id,

    field1

    FROM tdsMSMCA_Askk ORDER BY id

    OPEN cur

    FETCH NEXT FROM cur INTO

    @wt_row_id,

    @cookie_id

    WHILE @@FETCH_STATUS = 0

    BEGIN

    IF @last_@wt_row_id < @wt_row_id

    BEGIN

    IF @cookie_id ='H'

    BEGIN

    SET @session_id = @session_id + 1

    END

    SET @last_@wt_row_id= @wt_row_id

    UPDATE tdsMSMCA_Askk

    SET [NewID] = @session_id

    where id=@wt_row_id

    END

    FETCH NEXT FROM cur INTO @wt_row_id, @cookie_id

    END

    CLOSE cur

    DEALLOCATE cur

  • A solution composed just before bedtime, and it could serve from further testing:

    ;WITH CTE AS (

    SELECT legacyid, field1, newid,

    row_number() OVER(ORDER BY legacyid) as rowno,

    row_number() OVER(ORDER BY CASE field1 WHEN 'H' THEN 1 ELSE 2 END, legacyid) AS H_no

    FROM LoadTest

    ), CTE2 AS (

    SELECT legacyid, field1, newid,

    CASE field1 WHEN 'H' THEN H_no

    ELSE dense_rank() OVER (ORDER BY CASE WHEN field1 <> 'H' THEN rowno - H_no ELSE 1000000 END )

    END AS new_newid_value

    FROM CTE

    )

    UPDATE CTE2

    SET newid = new_newid_value

    go

    SELECT * FROM LoadTest ORDER BY legacyid

    [font="Times New Roman"]Erland Sommarskog, SQL Server MVP, www.sommarskog.se[/font]

  • SELECT

    l.legacyID,

    l.field1,

    [Newid] = DENSE_RANK() OVER(ORDER BY x.legacyID)

    FROM #LoadTest l

    OUTER APPLY (

    SELECT TOP 1 legacyID

    FROM #LoadTest i

    WHERE i.field1 = 'H'

    AND i.legacyID <= l.legacyID

    ORDER BY i.legacyID DESC) x

    ORDER BY l.legacyID

    β€œWrite the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw

    For fast, accurate and documented assistance in answering your questions, please read this article.
    Understanding and using APPLY, (I) and (II) Paul White
    Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

  • Thank you . It works .

Viewing 11 posts - 1 through 10 (of 10 total)

You must be logged in to reply to this topic. Login to reply