Find number in String and Return INT

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Find number in String and Return INT

ringovski

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August 8, 2013 at 12:33 am

#275961

Hi All,
I have a series of strings in a variable @buyer
3, RRRRR
4, SSSSS
5, DDDDDDDDDDD
6, AAAA
7, PPPPPP
8, UUUUUU
9, MMMMMM
10, LLLLLL
11, IIIII
12, EEEEE
and I only want to sub string the number then convert it to an INT, so i can use it in a where clause.
select *
from company
where company_id = CAST(SUBSTRING(@buyer,1,LEN(@buyer) - CHARINDEX(',',@buyer,0)) AS INT)
order by company_id
substring (@buyer, start at position 1,find length of @buyer minus the index position of the comma in @buyer) then cast int. but it doesn't work. say conversion failed when converting value 3,RRRRR.
I think it should be pretty simple, but I can't see it.
Thanks for any help.

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Koen Verbeeck SSC Guru Points: 259105 More actions · Answer 1

Try this:

DECLARE @buyer VARCHAR(10) = '12, RRRRR';

SELECT CAST(SUBSTRING(@buyer,1,CHARINDEX(',',@buyer,0) - 1) AS INT)

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ringovski Hall of Fame Points: 3521 More actions · Answer 2

ringovski

Hall of Fame

Points: 3521

August 8, 2013 at 5:26 pm

#1640023

Ah perfect Koen thanks heaps.

ScottPletcher SSC Guru Points: 101099 More actions · Answer 3

You might want to allow for no comma being in the string (just in case).

And you can remove some unnecessary elements from the code:

SELECT CAST(LEFT(@buyer, CHARINDEX(',', @buyer + ',') - 1) AS INT)

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Dwain Camps SSC Guru Points: 86948 More actions · Answer 4

Many ways to skin this proverbial cat:

WITH Buyers (buyer) AS (

SELECT '3, RRRRR'

UNION ALL SELECT '4, SSSSS'

UNION ALL SELECT '5, DDDDDDDDDDD'

UNION ALL SELECT '6, AAAA'

UNION ALL SELECT '7, PPPPPP'

UNION ALL SELECT '8, UUUUUU'

UNION ALL SELECT '9, MMMMMM'

UNION ALL SELECT '10, LLLLLL'

UNION ALL SELECT '11, IIIII'

UNION ALL SELECT '12, EEEEE'

)

SELECT 0+STUFF(buyer, PATINDEX('%[^0-9]%', buyer), 8000, '')

FROM Buyers

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