September 6, 2012 at 4:06 pm
my question is here is the example first
hour date sale
0 2012-09-05 10
1 2012-09-05 20
3 2012-09-05 30
4 2012-09-05 40
-- ------------- ----
23 2012-09-05 70
I want to sum up all the hours sale to day sale on this date
can any one help me pls..
Thanks
September 6, 2012 at 7:26 pm
Is this what you require ?
CREATE TABLE #T(Hr INT,D DATE,S INT)
INSERT INTO #T
SELECT 0, '2012-09-05', 10 UNION ALL
SELECT 1, '2012-09-05', 20 UNION ALL
SELECT 3, '2012-09-05', 30 UNION ALL
SELECT 4, '2012-09-05', 40 UNION ALL
SELECT 1, '2012-09-04', 20 UNION ALL
SELECT 1, '2012-09-03', 200 UNION ALL
SELECT 5, '2012-09-04', 2 UNION ALL
SELECT 23, '2012-09-05', 70
SELECT D AS 'Sales date',SUM(S) AS 'Total Sales' FROM #T GROUP BY D
Results:
Sales dateTotal Sales
2012-09-03200
2012-09-0422
2012-09-05170
September 7, 2012 at 1:39 am
this is the query
select DatePart(hour,Reading_Date) as hour, convert(Date,Reading_Date,103) as date, avg(Fuel_Level)as fuel_level,avg(Fuel_Volume)as fuel_volume from Levels
where Simmons_PanelID=5479 AND convert(Date,Reading_Date,103)='2012-09-05'
group by convert(Date,Reading_Date,103),DatePart(hour,Reading_Date)
order by DatePart(hour,Reading_Date)
outpur was :
02012-09-051081.91500010556.072500
12012-09-051081.45000010550.667500
22012-09-051080.94000010543.880000
32012-09-051073.56500010411.868500
42012-09-051063.21000010234.175500
52012-09-051056.00500010110.270500
62012-09-051041.2950009876.589000
72012-09-051022.1000009611.096000
82012-09-05998.0900009309.596000
92012-09-051413.25500013972.345500
102012-09-051535.83500015867.740000
112012-09-051516.81500015654.350500
122012-09-051499.52000015470.388000
132012-09-051485.86000015313.367000
142012-09-051469.06500015125.176000
152012-09-051450.85000014887.597000
162012-09-051431.66500014641.704500
172012-09-051407.25500014346.442500
182012-09-051374.46500013908.481500
192012-09-051354.15000013639.561000
202012-09-051344.24000013511.662500
212012-09-051336.61000013415.504500
222012-09-051330.81500013343.453500
232012-09-051327.36000013301.044500
my question is I want to sum up each hour to day
expected output:
hour date fuel_level fuel_volume
24 2012-09-05 540622 425621
after coming that I am trying to display week1 to week4 of that month
how to convert days to weeks pls
thanks
September 7, 2012 at 2:11 am
to add hours to days use the DATEADD function
today
select getdate()
today + 3 hours
select dateadd(hh, 3, getdate())
today - 3 hours
select dateadd(hh, -3, getdate())
today + 3 hours 1 week in the future
select DATEADD(ww, 1, DATEADD(hh, -3, getdate()))
My results were
2012-09-07 09:09:13.030
2012-09-07 12:09:13.030
2012-09-07 06:09:13.030
2012-09-14 06:10:27.403
-----------------------------------------------------------------------------------------------------------
"Ya can't make an omelette without breaking just a few eggs" 😉
September 7, 2012 at 9:02 am
vinay.varaala (9/7/2012)
this is the querywhere Simmons_PanelID=5479 AND convert(Date,Reading_Date,103)='2012-09-05'
Your where clause has rendered this nonSARGable. You don't need to convert your date to a formatted date string for this comparison.
where Simmons_PanelID=5479 AND Reading_Date = '2012-09-05'
Depending on your dateformat this would be fine. This way the optimizer can convert your constant to a datetime and then it can compare to the datetime in the table and your index will still be utilized (assuming you have one on Reading_Date).
_______________________________________________________________
Need help? Help us help you.
Read the article at http://www.sqlservercentral.com/articles/Best+Practices/61537/ for best practices on asking questions.
Need to split a string? Try Jeff Modens splitter http://www.sqlservercentral.com/articles/Tally+Table/72993/.
Cross Tabs and Pivots, Part 1 – Converting Rows to Columns - http://www.sqlservercentral.com/articles/T-SQL/63681/
Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs - http://www.sqlservercentral.com/articles/Crosstab/65048/
Understanding and Using APPLY (Part 1) - http://www.sqlservercentral.com/articles/APPLY/69953/
Understanding and Using APPLY (Part 2) - http://www.sqlservercentral.com/articles/APPLY/69954/
Viewing 5 posts - 1 through 4 (of 4 total)
You must be logged in to reply to this topic. Login to reply