from query results I need to group distinct data that has records in common.

  • I have a table pcid, part and the ruslts of the query look like this:

    (first I have a variable number in this case it's 3, could be 4, could be 2)

    1,a

    2,a

    1,b

    3,c

    1,d

    2,d

    3,d

    1,e

    2,f

    From this results I am interested in the 3 d's because there are 3 similar records of distinct column 1.

    How would you identify the d's in these results?

  • Not a lot to go on, but I'll take a shot:

    SELECT col1, col2

    FROM dbo.tablename

    GROUP BY col1, col2

    HAVING COUNT(DISTINCT col1) = (SELECT COUNT(DISTINCT col1) FROM dbo.tablename)

    SQL DBA,SQL Server MVP(07, 08, 09) "It's a dog-eat-dog world, and I'm wearing Milk-Bone underwear." "Norm", on "Cheers". Also from "Cheers", from "Carla": "You need to know 3 things about Tortelli men: Tortelli men draw women like flies; Tortelli men treat women like flies; Tortelli men's brains are in their flies".

  • This might help:

    --Creating Table

    Create Table Ex1

    (Col1 int,

    Col2 char(1) )

    --Inserting Sample Data

    Insert Into Ex1

    Select 1, 'a'

    Union ALL

    Select 2, 'a'

    Union ALL

    Select 1, 'b'

    Union ALL

    Select 3, 'c'

    Union ALL

    Select 1, 'd'

    Union ALL

    Select 2, 'd'

    Union ALL

    Select 3, 'd'

    Union ALL

    Select 1, 'e'

    Union ALL

    Select 2, 'f'

    --If it is for simple Identification yo can add an Id column using Row_Number() Over Partition

    Select ROW_NUMBER() Over (Order By (Select NULL) ) As Id, * From Ex1

    --Otherwise you can group the data according to col1 and then use Row_Number() Over Partition

    Select *, ROW_NUMBER() Over (Partition By Col1 Order By Col2) as rn From Ex1

    If these queries don't work then you would have to elaborate on your requirement a little more.

    Vinu Vijayan

    For better and faster solutions please check..."How to post data/code on a forum to get the best help" - Jeff Moden[/url] 😉

Viewing 3 posts - 1 through 2 (of 2 total)

You must be logged in to reply to this topic. Login to reply