May 7, 2010 at 11:12 am
column1
\\xyz.se.df.a.b\fgd\
colum2
\\xyz\fgd\
now i want to join both the coulmns by elimating the highlighted part. i mean .se.df.a.b
or else just give me the query which can elimante that part from that string
May 7, 2010 at 11:19 am
neliii (5/7/2010)
column1\\xyz.se.df.a.b\fgd
colum2
\\xyz\fgd
now i want to join both the coulmns by elimating the highlighted part. i mean .se.df.a.b
or else just give me the query which can elimante that part from that string
I am not sure if this is what you want, but it is what I read.
UPDATE YourTable
SET Column1 = Column2
WHERE YourWhereClause
-- Cory
May 7, 2010 at 11:26 am
i need a query to eliminate that highlited part of the string so that after elimination it looks like the row in colum2
May 7, 2010 at 11:36 am
My query will do that. you want col1 to be the same as col2.
-- Cory
May 7, 2010 at 11:43 am
neliii (5/7/2010)
column1\\xyz.se.df.a.b\fgd
colum2
\\xyz\fgd
now i want to join both the coulmns by elimating the highlighted part. i mean .se.df.a.b
or else just give me the query which can elimante that part from that string
Do you mean, something like:
select replace ( '\\xyz.se.df.a.b\fgd\' , '.se.df.a.b' , '' )
_____________________________________
Pablo (Paul) Berzukov
Author of Understanding Database Administration available at Amazon and other bookstores.
Disclaimer: Advice is provided to the best of my knowledge but no implicit or explicit warranties are provided. Since the advisor explicitly encourages testing any and all suggestions on a test non-production environment advisor should not held liable or responsible for any actions taken based on the given advice.May 7, 2010 at 11:44 am
@cory
Thankq cory
i got it.
And for now lets forget about column2
i jus want to eliminate that part of string. Can u help me with query whihc will eliminate that part.
I really appriciate ur help for me
May 7, 2010 at 11:44 am
Here is an example to get rid of everything after the first "." and before the third "\". You provided very little info, so I don't know if that's exactly what you're wanting to do but it was my best guess.
select stuff('\\xyz.se.df.a.b\fgd\', charindex('.', '\\xyz.se.df.a.b\fgd\'), charindex('\', '\\xyz.se.df.a.b\fgd\', 3) - charindex('.', '\\xyz.se.df.a.b\fgd\') - 1, '')
May 7, 2010 at 11:48 am
Actually, I should do it like this so it may be more clear:
declare @vc_string varchar(20);
select @vc_string = '\\xyz.se.df.a.b\fgd\';
select stuff(@vc_string, charindex('.', @vc_string), charindex('\', @vc_string, 3) - charindex('.', @vc_string) - 1, '');
May 7, 2010 at 11:50 am
Thanks for ur help
what if i got different rows in that column like
example:
Colum1
\\xyz.ed.kl.e.a\fgd\\rsq.fd.ij.g.b\fgd\\wes.as.gh.c.b\fgd\\abc.er.tf.h.d\fgd
what if i want to get the rows with the part of the string starting from like .ed.kl.e.a i mean starting from . to \ eliminated in all the rows.
May 7, 2010 at 12:09 pm
DECLARE @STR NVARCHAR(30)
SET @STR = '\\xyz.ed.kl.e.a\fgd\'
SELECT SUBSTRING(@str, 1, CHARINDEX('.', @STR) - 1) + SUBSTRING(@str, CHARINDEX('\', @STR, 3), 4)
, SUBSTRING(@str, 1, CHARINDEX('.', @STR) - 1) + SUBSTRING(@str, CHARINDEX('\', @STR, CHARINDEX('.', @STR) - 1), 4)
My result for the one test is:
\\xyz\fgd
-- Cory
May 7, 2010 at 12:15 pm
May 7, 2010 at 12:17 pm
bteraberry (5/7/2010)
Mine was more efficient. Plus STUFF is simply cool and underused.
Props on the STUFF, in 12 years of doing SQL, that's the first time I have ever seen it used except in BOL/MSDN examples.
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May 7, 2010 at 12:19 pm
GregoryF (5/7/2010)
bteraberry (5/7/2010)
Mine was more efficient. Plus STUFF is simply cool and underused.Props on the STUFF, in 12 years of doing SQL, that's the first time I have ever seen it used except in BOL/MSDN examples.
Heh, thanks.
And here is the whole example:
declare @t_temp table
(Column1 varchar(50));
insert into @t_temp
select '\\xyz.ed.kl.e.a\fgd\' union
select '\\rsq.fd.ij.g.b\fgd\' union
select '\\wes.as.gh.c.b\fgd\' union
select '\\abc.er.tf.h.d\fgd\';
/* and the actual function ... */
select stuff(Column1, charindex('.', Column1), charindex('\', Column1, 3) - charindex('.', Column1) - 1, '')
from @t_temp;
May 7, 2010 at 12:23 pm
Thanks! I have used stuff once or twice - you are correct - underused!
-- Cory
May 7, 2010 at 12:30 pm
@ all
thank you guys..
i got it..
but i got one more qstn
i got another row in that
\\xyz.ed.kl.e.a\fgd\\rsq.fd.ij.g.b\fgd\\wes.as.gh.c.b\fgd\\abc.er.tf.h.d\fgd\\eds\fgd
now when i'm trying to print the result for all the rows after eliminationg the string after . to
my result is like
\\xyz\fgd\\rsq\fgd\\wes\fgd\\abc\fgdNULL
the last row is getting as null
but i want the result to be
\\xyz\fgd\\rsq\fgd\\wes\fgd\\abc\fgd\\eds\fgd
Can u help me out with that ASAP
Thanq In advance
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