January 28, 2011 at 6:36 am
Hello Friends,
I am having a table Item_Master that are having more than 2 crore rows and the structure of table is
as
codeitem_code
1RS344
1RS344
1RS344
2RS355
2RS355
3RS356
3RS356
3RS356
3RS356
i need append a column with value in that column like
codeitem_codeItem_value
1RS344 1
1RS344 2
1RS344 3
2RS355 1
2RS355 2
3RS356 1
3RS356 2
3RS356 3
3RS356 4
the result contain only a index column inwhich indexing start from one up to....n and is depend on grouping 'code' field
what is the shortest way to get this result.
is there any way by which we can use 'partition by' clause in sql statement?
or any other way?
send whole sql select statement or function or cursor which make it fast?
Thanks!!
January 28, 2011 at 7:08 am
what have you tried? I won't provide the code right away, since it doesn't look like you've given it a try. Depending on the size of the table, the approach may differ. I would probably create a temp table with the indexing that you require, then use a cte to insert into it. The cte would generate the new code on the fly. Then you can rename the tables and drop the original table.
For better, quicker answers, click on the following...
http://www.sqlservercentral.com/articles/Best+Practices/61537/
For better answers on performance questions, click on the following...
http://www.sqlservercentral.com/articles/SQLServerCentral/66909/
January 28, 2011 at 10:05 am
Please add the ddl and row insert statements next time.
This is just a quick and dirty to do the numbering...
declare @test-2 table (code int , item_code nvarchar(10) )
INSERT INTO @test-2 (code , item_code)
SELECT 1 ,'RS344'
UNION ALL SELECT 1, 'RS344'
UNION ALL SELECT 1, 'RS344'
UNION ALL SELECT 2, 'RS355'
UNION ALL SELECT 2, 'RS355'
UNION ALL SELECT 3, 'RS356'
UNION ALL SELECT 3, 'RS356'
UNION ALL SELECT 3, 'RS356'
UNION ALL SELECT 3, 'RS356'
SELECT
ROW_NUMBER() OVER (PARTITION BY code,item_code ORDER BY code,item_code)
,*
FROM @test-2
January 28, 2011 at 10:08 pm
Thanks Friend!!
You have solved my problem i am vary thankful to u.
Thank u again!!
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