June 23, 2010 at 11:44 pm
Hi All,
Here is my SQL Query, This query should not fetch duplicate contactID(i.e Same ContactID).but when i execute the query i get duplicated ContactID.I know it is a problem with Joins. Could anyone tell me what is wrong with my Query,
Here is my query
select ContactTracking.Contact_ID
FROM
ContactTracking ContactTracking
LEFT OUTER JOIN Issues Issues ON ContactTracking.Issue_ID = Issues.Issue_ID
LEFT OUTER JOIN HRA hra ON hra.HcnID = ContactTracking.HcnID
INNER JOIN HPS_COMMON.dbo.wrk_user wrk_User ON ContactTracking.UserID = wrk_User.id_User
INNER JOIN HPS_COMMON.dbo.def_Usertype def_Usertype ON wrk_User.id_UserType = def_Usertype.id_UserType
WHERE
ContactTracking.contact_date>'10-jan-2009'
AND ContactTracking.Call_end_time is not null
AND Contact_ID in ('122734','122738')
And here is the ContactId result i get,
122734
122734
122738
122738
June 24, 2010 at 12:21 am
Vinay,
Add some sample data and expected result.
So it will help u help us
June 24, 2010 at 12:25 am
Post DDL, DML statements in readily consumable format for faster response...
June 24, 2010 at 12:29 am
Some sample datas are,
122731
122732
122733
122734
122735
122736
122737
122738
122739
According to the Query the Expected result is,
122734
122738
But i am getting as,
122734
122734
122738
122738
June 24, 2010 at 3:24 am
Hi there,
There's nothing wrong with your query.. Use DISTINCT keyword to eliminate the duplicate values..
Syntax here:
SELECT DISTINCT <column 1>, ... <column N>
FROM <table>
Just a side note, alias name is mostly used to shorten the name of the table.. 🙂
Cheers
June 24, 2010 at 3:36 am
Or Use group by claue for your id
June 24, 2010 at 3:08 pm
If your sole aim is to return Distinct ContactId's then introducing a Distinct or Group By clause should
fix it but you may want to go over what it is you are actually trying to achieve. The sample data you have provided is insufficient for us to determine this.
Bear in mind that if records in the ContactTracking Table have many matches in the joined Tables then the result would include duplication of the ContactIds.
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