Nth root of a number

• vallisaravanan

  SSC Eights!

  Points: 914

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  November 25, 2008 at 12:54 am

  #196813

  Hi,

  I am trying to calculate CAGR which when computed for two years, the formula is (Annual Turnover ^ 1/2)-1 and when computed for three years, the formula is (Annual Turnover ^1 / 3)-1 and when computed for four years, the formula is (Annual Turnover ^ 1/4)-1.

  So, Can anybody suggest me how we can get the nth root of a number in SQL? I tried using power(Annual Turnover,(1/n)). It doesn't work.

  Thanks in advance,

  Valli

• SwePeso

  SSC-Dedicated

  Points: 39757

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  November 25, 2008 at 2:19 am

  #902971

  3rd root of 27 is calculated as (the positive value)

  SELECT POWER(27.0E, 1.0E / 3.0E)

  ---

  N 56°04'39.16"
  E 12°55'05.25"

• jgchipster

  Newbie

  Points: 7

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  November 26, 2008 at 8:52 am

  #903829

  See this post: http://www.sqlservercentral.com/Forums/Topic239436-8-1.aspx

  Not sure how you are doing your calcs, but the script below will take the 2nd, 3rd, 4th and 5th root of the number 27.

  DECLARE

  @nthRoot INT

  ,@AnnualTurnover INT

  ,@x INT

  SET @AnnualTurnover = 27

  SET @x = 2

  WHILE @x <= 5

  BEGIN

  SET @nthRoot = @x

  SELECT

  @AnnualTurnover '@AnnualTurnover'

  ,@nthRoot 'nthRoot'

  ,POWER(CAST(@AnnualTurnover AS FLOAT),(CAST(1 AS FLOAT)/CAST(@nthRoot AS FLOAT))) 'Result'

  SET @x = @x + 1

  END