October 23, 2008 at 12:05 pm
Is there a quick and easy way to extract just the hour and day from a column with the type of datetime?
For example if the entry is...
12/15/1997 11:59:00 PM
....I'd like to format it so that I get a 23 (military time) for the hour and Monday (or Mon) for the day result. I'd want the result in 2 separate columns.
I figured out how to do this with Excel but I'd rather not mess with Excel on this project.
October 23, 2008 at 12:34 pm
Try the DATEPART and DATENAME functions
Gail Shaw
Microsoft Certified Master: SQL Server, MVP, M.Sc (Comp Sci)
SQL In The Wild: Discussions on DB performance with occasional diversions into recoverability
October 23, 2008 at 12:36 pm
I found this in BOL under DATEPART
DECLARE @date DATETIME
SET @date = '12/15/1997 11:59:00 PM'
SELECT DATENAME(dw,@date),DATEPART(hh,@date)
Greg
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The glass is at one half capacity: nothing more, nothing less.
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