varchar issue

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varchar issue

BeginnerBug

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October 25, 2010 at 11:44 pm

#143782

i am getting following exception while attempting to set a alphanumeric value to varchar variable... what would be the reason?... cant i have number at the end of varchar variable?... we cant blame user if he enter number at end of a varchar variable?... any help pls
@PVC_APPLICATION_NAMEVARCHAR(50)
SET @PVC_APPLICATION_NAME='APPLICATION NAME1 '
Conversion failed when converting the varchar value 'APPLICATION NAME1 ' to data type int.

Viewing 6 posts - 1 through 5 (of 5 total)

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Iulian -207023 SSCertifiable Points: 7639 More actions · Answer 1

You have to use DECLARE statement in order to declare a variable. I tried this

DECLARE @PVC_APPLICATION_NAME VARCHAR(50)

SET @PVC_APPLICATION_NAME='APPLICATION NAME1 '

PRINT @PVC_APPLICATION_NAME

and it showed me as result: "APPLICATION NAME1 "

Regards,

Iulian

VENUGOPAL.RR Ten Centuries Points: 1395 More actions · Answer 2

Please check what type of variable u have declared for @PVC_APPLICATION_NAME.

I think u have declared as INT....

BeginnerBug Hall of Fame Points: 3539 More actions · Answer 3

DECLARE @PVC_LOGIN_USERVARCHAR(40),

@PVC_APPLICATION_IDVARCHAR(40),--yet to finish

@PVC_PROGRAM_NAMEVARCHAR(40),

@PI_RET_STATUSINT,

@PVC_RET_MSGVARCHAR(500),

@PI_RET_ERRORNUMINT,

@PVC_APPLICATION_NAMEVARCHAR(50), @pvc_dest int;

my declaration is mentioned above

Hardy21 SSCrazy Eights Points: 9708 More actions · Answer 4

MonsterRocks (10/26/2010)
DECLARE @PVC_LOGIN_USERVARCHAR(40), @PVC_APPLICATION_IDVARCHAR(40),--yet to finish @PVC_PROGRAM_NAMEVARCHAR(40), @PI_RET_STATUSINT, @PVC_RET_MSGVARCHAR(500), @PI_RET_ERRORNUMINT,
@PVC_APPLICATION_NAMEVARCHAR(50), @pvc_dest int;
my declaration is mentioned above

As per the declaration above, I dont see any errors while executing the below code:

DECLARE @PVC_LOGIN_USER VARCHAR(40),

@PVC_APPLICATION_ID VARCHAR(40), --yet to finish

@PVC_PROGRAM_NAME VARCHAR(40),

@PI_RET_STATUS INT,

@PVC_RET_MSG VARCHAR(500),

@PI_RET_ERRORNUM INT,

@PVC_APPLICATION_NAME VARCHAR(50),

@pvc_dest int ;

SET @PVC_APPLICATION_NAME = 'APPLICATION NAME1 '

PRINT @PVC_APPLICATION_NAME

Thanks

William Vach SSCertifiable Points: 5551 More actions · Answer 5

The statements that you provided appear to be correct. Are you sure that the set command is getting the error? Could you be assigning the PVC_APPLICATION_NAME variable to an int variable or column later in the code?