ROUND() function doesn't round properly

  • Hello. I use SQL Server 2005 and I'm calculating the age of patients in the following manner:

    DATEDIFF(DAY, birthdate, operationdate)/365.25

    The output always seems to be a decimal with 6 decimal digits. The rounding problem arises with border cases like for instance an age of 60.444445. If you round this properly it should result in 60.45 and that should result in 60.5. However, when I use [font="Courier New"]ROUND(60.444445, 1)[/font] it results in 60.4!

    The problem is that SQL Server seems to ignore the digits after the rounding border. [font="Courier New"]ROUND(60.449999, 1)[/font] for instance also results in 60.4. It seems to truncate it 1 position behind the rounding index and starts rounding after that.

    I found out that using the ROUND() function repeatedly in the following manner solves the issue but it is a bit ridiculous:

    PRINT ROUND(ROUND(ROUND(ROUND(ROUND(60.444445, 5), 4), 3), 2), 1)

    Is there any other way to solve this and am I missing something?

    Thanks in advance!

  • Heres how to calculate an age

    select CASE

    WHEN dateadd(year, datediff (year, d1, d2), d1) > d2

    THEN datediff (year, d1, d2) - 1

    ELSE datediff (year, d1, d2)

    END as Age

    I'll take a look at the rounding issue though...



    Clear Sky SQL
    My Blog[/url]

  • I think you are wrong in your assessment of round though,

    round(60.444445,1) = 60.4

    This

    PRINT ROUND(ROUND(ROUND(ROUND(ROUND(60.444445, 5), 4), 3), 2), 1)

    works because you are rounding a rounded , rounded, rounded , rounded number (ie the 5 has for want of a better word been cascaded up)



    Clear Sky SQL
    My Blog[/url]

  • For some reason that way of rounding was in my head. But I spoke with others about and I think SQL Server does round it correctly yes.

  • Dave Ballantyne (10/2/2009)


    Heres how to calculate an age

    select CASE

    WHEN dateadd(year, datediff (year, d1, d2), d1) > d2

    THEN datediff (year, d1, d2) - 1

    ELSE datediff (year, d1, d2)

    END as Age

    I'll take a look at the rounding issue though...

    That's one of the simplest I've seen. Correctly handles the Feb 29 problem that most other's don't handle, too!

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

    Change is inevitable... Change for the better is not.


    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)

  • Shoot... the link is broken. Thanks anyway, Dave.

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

    Change is inevitable... Change for the better is not.


    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)

  • Seems fine now, just a temporary thing i guess.

    TBH , its hardly worth the click though 🙂 simple Q and A



    Clear Sky SQL
    My Blog[/url]

  • Hmmmm.... something must be wrong on my end. It keeps giving me a 404 error.

    Q & A's are sometimes pretty rich in information like the little date jewel you found.

    --Jeff Moden


    RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    ________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

    Change is inevitable... Change for the better is not.


    Helpful Links:
    How to post code problems
    How to Post Performance Problems
    Create a Tally Function (fnTally)

  • DECLARE @test-2 TABLE (

    EmpName VARCHAR(40) ,

    BirthDate DATE

    );

    INSERT INTO @test-2 ( EmpName , BirthDate

    )

    VALUES ( '30 Yrs old yesterday' , DATEADD(day , -1 , DATEADD(year , -30 , GETDATE()))

    ) , ( '30 Yrs old today' , DATEADD(year , -30 , GETDATE())

    ) , ( '30 Yrs old tomorrow' , DATEADD(day , 1 , DATEADD(year , -30 , GETDATE()))

    );

    SELECT EmpName , BirthDate ,

    CASE

    WHEN DATEADD(YY , DATEDIFF(yy , BirthDate , GETDATE()) , BirthDate) < GETDATE()

    THEN DATEDIFF(yy , BirthDate , GETDATE())

    ELSE DATEDIFF(yy , BirthDate , GETDATE()) - 1

    END AS Age

    FROM @test-2;

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