i need logic to get the days for most recent week that ends with Friday

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i need logic to get the days for most recent week that ends with Friday

purushotham.k9

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Points: 1992
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December 21, 2009 at 5:53 am

#136865

can some please let me kow the procedure to get the most week days(i.e the most recent firiday is 18th So i need to get the days like 12,13,14,15,16,17 and 18.

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Lynn Pettis SSC Guru Points: 442467 More actions · Answer 1

Something like this?

declare @TestDate datetime;

set @TestDate = '2009-12-19';

select dateadd(wk,datediff(wk,0,@TestDate + 1),-9),dateadd(wk,datediff(wk,0,@TestDate + 1),-3)

set @TestDate = '2009-12-24';

select dateadd(wk,datediff(wk,0,@TestDate + 1),-9),dateadd(wk,datediff(wk,0,@TestDate + 1),-3)

Lowell SSC Guru Points: 323518 More actions · Answer 2

dates can seem tricky until you get used to them.

never convert a date to varchar or anything...always keep them in datetime .

this will give you the Monday of the current week; if you need LAST monday, you'd deduct one more week from it for monday, and add 5 days to it to get that friday:

--Monday of the Current Week

select DATEADD(wk, DATEDIFF(wk,0,getdate()), 0)

--Monday of "Last Week":

select DATEADD(wk,-1,DATEADD(wk, DATEDIFF(wk,0,getdate()),0))

--FRIDAY of "Last Week":(Monday minus 3 days, or Monday +4

select DATEADD(dd,-3,DATEADD(wk, DATEDIFF(wk,0,getdate()),0))

select DATEADD(dd,4,DATEADD(wk,-1,DATEADD(wk, DATEDIFF(wk,0,getdate()),0)))

Lowell

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Old McDonald SSCertifiable Points: 5768 More actions · Answer 3

declare @lastFriday datetime

SET @lastFriday = convert(datetime,convert(varchar(10),getdate() - (datepart(w,getdate())+1),121))

select

@lastFriday - 6

,@lastFriday - 5

,@lastFriday - 4

,@lastFriday - 3

,@lastFriday - 2

,@lastFriday - 1

,@lastFriday

-Vikas Bindra

Lynn Pettis SSC Guru Points: 442467 More actions · Answer 4

vikas bindra (12/21/2009)
declare @lastFriday datetime SET @lastFriday = convert(datetime,convert(varchar(10),getdate() - (datepart(w,getdate())+1),121)) select @lastFriday - 6 ,@lastFriday - 5 ,@lastFriday - 4 ,@lastFriday - 3 ,@lastFriday - 2 ,@lastFriday - 1
,@lastFriday

You don't need to convert to character format. Keep your date calculations using datetime values.

Nabha SSCrazy Eights Points: 8534 More actions · Answer 5

All good answers above,

one more way to find your last friday, (and then deduce your other days)

Select dateadd(day, - (datepart(dw, getdate())+1), getdate())

---------------------------------------------------------------------------------

Old McDonald SSCertifiable Points: 5768 More actions · Answer 6

Lynn Pettis (12/21/2009)
vikas bindra (12/21/2009)
declare @lastFriday datetime SET @lastFriday = convert(datetime,convert(varchar(10),getdate() - (datepart(w,getdate())+1),121)) select @lastFriday - 6 ,@lastFriday - 5 ,@lastFriday - 4 ,@lastFriday - 3 ,@lastFriday - 2 ,@lastFriday - 1
,@lastFriday
You don't need to convert to character format. Keep your date calculations using datetime values.

I am converting to varchar to ignore the time part and get only the date.

Is there any other to remove the time part?

-Vikas Bindra

Nabha SSCrazy Eights Points: 8534 More actions · Answer 7

Is there any other to remove the time part?

Select dateadd(day, 0, datediff(day, 0, getdate()))

---------------------------------------------------------------------------------

Lynn Pettis SSC Guru Points: 442467 More actions · Answer 8

vikas bindra (12/21/2009)
Lynn Pettis (12/21/2009)
vikas bindra (12/21/2009)
declare @lastFriday datetime SET @lastFriday = convert(datetime,convert(varchar(10),getdate() - (datepart(w,getdate())+1),121)) select @lastFriday - 6 ,@lastFriday - 5 ,@lastFriday - 4 ,@lastFriday - 3 ,@lastFriday - 2 ,@lastFriday - 1
,@lastFriday
You don't need to convert to character format. Keep your date calculations using datetime values.
I am converting to varchar to ignore the time part and get only the date.
Is there any other to remove the time part?

Don't need to ignore the time portion. For one, check out the code I posted. It doesn't care what the time portion is. Also, you drop the the time like this:

dateadd(dd, datediff(dd, 0, getdate()), 0)

Old McDonald SSCertifiable Points: 5768 More actions · Answer 9

vikas bindra (12/21/2009)
Lynn Pettis (12/21/2009)
vikas bindra (12/21/2009)
declare @lastFriday datetime SET @lastFriday = convert(datetime,convert(varchar(10),getdate() - (datepart(w,getdate())+1),121)) select @lastFriday - 6 ,@lastFriday - 5 ,@lastFriday - 4 ,@lastFriday - 3 ,@lastFriday - 2 ,@lastFriday - 1
,@lastFriday
You don't need to convert to character format. Keep your date calculations using datetime values.
I am converting to varchar to ignore the time part and get only the date.
Is there any other to remove the time part?

Cool. Thanks for showing this. it looks better than converting to varchar

-Vikas Bindra

Lynn Pettis SSC Guru Points: 442467 More actions · Answer 10

vikas bindra (12/21/2009)
vikas bindra (12/21/2009)
Lynn Pettis (12/21/2009)
vikas bindra (12/21/2009)
declare @lastFriday datetime SET @lastFriday = convert(datetime,convert(varchar(10),getdate() - (datepart(w,getdate())+1),121)) select @lastFriday - 6 ,@lastFriday - 5 ,@lastFriday - 4 ,@lastFriday - 3 ,@lastFriday - 2 ,@lastFriday - 1
,@lastFriday
You don't need to convert to character format. Keep your date calculations using datetime values.
I am converting to varchar to ignore the time part and get only the date.
Is there any other to remove the time part?
Cool. Thanks for showing this. it looks better than converting to varchar

You can also check out my blog post Some Common Date Routines.

Old McDonald SSCertifiable Points: 5768 More actions · Answer 11

Old McDonald

SSCertifiable

Points: 5768

December 21, 2009 at 7:16 am

#1094739

Thanks Lynn!

-Vikas Bindra

purushotham.k9 SSCommitted Points: 1992 More actions · Answer 12

I have got the expected result, but i need to display the header like Dec 18 2009, dec 17 2009.....dec 12 2009..Can you please help me to get in this format

Lynn Pettis SSC Guru Points: 442467 More actions · Answer 13

How about you show us what you have tried first. Maybe we'll what you are doing wrong and help you that way instead of just giving you the answer.

Jeff Moden SSC Guru Points: 1004409 More actions · Answer 14

vikas bindra (12/21/2009)
Cool. Thanks for showing this. it looks better than converting to varchar

Over a fair number of rows, it's also quite a bit faster because it doesn't have to go through a string based conversion.

--Jeff Moden

RBAR is pronounced "ree-bar" and is a "Modenism" for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
________Stop thinking about what you want to do to a ROW... think, instead, of what you want to do to a COLUMN.

Change is inevitable... Change for the better is not.

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