duplicate entries in a field

Question

Post reply

duplicate entries in a field

sindhigrl

Default port

Points: 1448
More actions
August 31, 2006 at 1:26 pm

#113492

I have a field that holds address and city. For some reason the app populated the city twice- for example: 123 Anywhere Place, NY, NY but it should be 123 Anywhere Place, NY. The app is fixed, but now I have to fix all the records this has affected(about 2000) - How would I write an update statement that only updates the records with duplicate cities?

Thanks!
Thanks!

Viewing 15 posts - 1 through 15 (of 20 total)

You must be logged in to reply to this topic. Login to reply

Bhushan Default port Points: 1427 More actions · Answer 1

update Customer

set address = LEFT (address, LEN(address) - CHARINDEX(',', REVERSE(address)))

Gopi Muluka SSCarpal Tunnel Points: 4594 More actions · Answer 2

TRY THIS

Assumed ',' will be the separator between the duplicates and repeated city name is the last word in the Address

Ex: Updated Name column in Tab_Test table

UPDATE TAB_TEST

SET NAME=reverse(substring(reverse(rtrim(name)),charindex(',',reverse(rtrim(name)))+1, len(reverse(rtrim(name))) ))

Gopi Muluka SSCarpal Tunnel Points: 4594 More actions · Answer 3

You can try this also

update Tab_test

set name=LEFT (name, LEN(rtrim(name)) - CHARINDEX(',', REVERSE(rtrim(name))))

Added rtrim to Nagabhushanam approach

sindhigrl Default port Points: 1448 More actions · Answer 4

Thanks, but both of these update statements get rid of both instances of the city. I need to retain one of the cities. Any ideas?

Thanks!

Ninja's_RGR'us SSC Guru Points: 294069 More actions · Answer 5

R u sure???

LEFT

(name, LEN(rtrim(name)) - CHARINDEX(',', REVERSE(rtrim(name)))) works fine for me.

Nice code BTW.... I need to start using this reverse function more often...

Gopi Muluka SSCarpal Tunnel Points: 4594 More actions · Answer 6

I assumed that duplicate city is separated by ','

If not, what are all the characters separating two values.

If both are not separated by any of the characters then what is the length of city is it variable?

sindhigrl Default port Points: 1448 More actions · Answer 7

Sorry- you are correct, these statements do work. When I tested it - it showed me also the records that do not have a city whatsoever. But it does work on eliminating one instance of the city on the records with dups. Thank you so much for you help!!

Thanks!

sindhigrl Default port Points: 1448 More actions · Answer 8

ok- I just tried it in a test table and it doesn't work.

This is the update statement I'm using:

update Tab_test

set name=LEFT (name, LEN(rtrim(name)) - CHARINDEX(',', REVERSE(rtrim(name))))

Records that were 123 Anywhere Pl,NY,NY are now

123 Anywhere Pl,NY (which is good)

But the ones that were correct are now

123 Anywhere Pl

I'm not sure how to make this work.

thanks!

Thanks!

Gopi Muluka SSCarpal Tunnel Points: 4594 More actions · Answer 9

I created a function to count the commas in the address field like

Create Function CountCommas(@str varchar(4000)) returns int as

begin

Declare @i int,

@count int

set @i=1

set @count=0

while @i>0

begin

set @i =charindex(',',@str)

set @STR=substring(@str,@i+1,len(@str))

set @count=@count+1

end

return @count-1

end

Now update statment will be

update Tab_test

set name=case dbo.countcommas(name) when 0 then name when 1 then name else LEFT (name, LEN(rtrim(name)) - CHARINDEX(',', REVERSE(rtrim(name)))) end

This statement also have the limitation that if Address contains more than 1 comma it fails

sindhigrl Default port Points: 1448 More actions · Answer 10

So, that wouldn't work either for my situation- right? I need to get rid of the second city after the second comma...but if there is only one comma, leave it be. I'm not sure if this is possible.

Thanks!

Sergiy SSC Guru Points: 110208 More actions · Answer 11

Anita,

your application is not fixed!!!

As I can see user enters parts of address into separate fields, and application concatenates it into one string before saving it in database.

STOP IT!

Fix the application and probably your database as well.

Store information in the smallest bits are available for you.

It's not a big deal to concatenate parts into one string when you really need one string.

But it becomes a real headache when you need to extract part of your string for seaching, grouping, etc.

For example, when you need all addresses from NY city, but not from NY state. And you must consider that strings "N.Y.", "New York", "New York City", "N Y" are probably the same as "NY" from business point of view. And not to mess up with "123 NY Place, Freaky Town"

_____________
Code for TallyGenerator

sindhigrl Default port Points: 1448 More actions · Answer 12

This is a vendor product - and they are not willing to take the city out of that field.This The city is also stored in it's own separate field and believe me I've tried to get them to fix it so that the city is not stored also with the location...but no luck. For now I have to live with it and clean up the mess.

Anyway, thank you everyone for your help, but I've figured out a way to fix it. Since there are only 6 possible cities...I ran 6 update statement that look like this and it's worked:

Update table

Set location = Case when Location like

'%,NY,NY' then LEFT (location, LEN(rtrim(location)) - CHARINDEX(',', REVERSE(rtrim(location))))

Else location

end

Thanks!

Sergiy SSC Guru Points: 110208 More actions · Answer 13

If vendor could fix one error then they could fix and another one.

But if you have city stored in separate column your task becomes really easy:

Update table

Set location = REPLACE (Location, ',' + City + ','+ City, ','+ City)

Check out if you need space after comma in ','

_____________
Code for TallyGenerator

Magnus Wikegard Newbie Points: 3 More actions · Answer 14

Try this,

should work with any duplicate comma separated endings

UPDATE

table

SET

Location=LEFT (Location, LEN(RTRIM(Location)) - CHARINDEX(',', REVERSE(RTRIM(Location))))

WHERE

CHARINDEX(

SUBSTRING(

RTRIM(Location),

LEN(LEFT (Location, LEN(rtrim(Location)) - CHARINDEX(',', REVERSE(RTRIM(Location)))))+1,

CHARINDEX(',', REVERSE(RTRIM(Location)))),

LEFT(Location,LEN(RTRIM(Location)) - CHARINDEX(',', REVERSE(RTRIM(Location))))

)>0

Magnus W