All the Costs of Downtime
Downtime causes a lot of problems, not all of which are financial for an organization.
2025-09-22
122 reads
Downtime causes a lot of problems, not all of which are financial for an organization.
2025-09-22
122 reads
Steve talks about the process of decision making with idea for shortening the time taken.
2025-06-09
87 reads
2025-04-09
196 reads
An Azure datacenter had a failure after an incident, partially because they didn't have enough people. Steve notes that staffing is a challenge in many ways.
2023-09-29
171 reads
The way we view our jobs might change how we do them. Steve has some advice on how to think about the work you do.
2023-09-27
109 reads
Helping your business get value from a digital transformation can start within your own team or group.
2023-02-08
108 reads
When I first started working in technology in the 90s, it was a time of outsourcing lots of work overseas. Many large companies followed the wave of manufacturing in the 70s and 80s by many companies, including lots of semi-conductor manufacturers. I watched as a number of jobs moved overseas, though fortunately not mine. In […]
2023-02-06
157 reads
By Brian Kelley
I will be leading an in-person Certified Information Systems Auditor (CISA) exam prep class...
EightKB is back again for 2026! The biggest online SQL Server internals conference is...
By HeyMo0sh
Working in DevOps long enough teaches you two universal truths: That’s exactly why I...
Hi all, I just started using VS Code to work with DB projects. I...
Comments posted to this topic are about the item Fun with JSON II
Comments posted to this topic are about the item Changing Data Types
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
t2.*
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t1
CROSS APPLY OPENJSON(t1.value) t2; See possible answers