2025-01-10
1,826 reads
2025-01-10
1,826 reads
2024-05-29
295 reads
This article looks at deploying SQL Server on an Azure VM from Azure Data Studio.
2023-05-24
1,510 reads
This article looks at database migration with the Azure Data Studio extension, making it easy to move databases from an on premises SQL Server to one in Azure.
2021-09-20
7,422 reads
Learn how to create an Azure VM image that can be used to quickly deploy new Azure VMs that are preconfigured based on your image settings.
2021-02-02
2020-10-16
429 reads
2019-07-25
710 reads
This article provides pricing guidance for SQL Server virtual machines in Azure.
2018-12-03
3,357 reads
The whole point of using a cloud service is to be able to use it intensively for a brief period just when it is needed and then clear out all your work when you've finished. This means automation to make the process as quick and easy as possible. It is likely to mean creating a VM, provisioning it from scratch and spinning it up using PowerShell. Relax, grab the popcorn, and let Adam Bertram show you how he does it in Azure.
2016-02-18
5,142 reads
By Brian Kelley
I will be leading an in-person Certified Information Systems Auditor (CISA) exam prep class...
EightKB is back again for 2026! The biggest online SQL Server internals conference is...
By HeyMo0sh
Working in DevOps long enough teaches you two universal truths: That’s exactly why I...
Hi all, I just started using VS Code to work with DB projects. I...
Comments posted to this topic are about the item Fun with JSON II
Comments posted to this topic are about the item Changing Data Types
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
t2.*
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t1
CROSS APPLY OPENJSON(t1.value) t2; See possible answers